የ12ኛ ክፍል ውጤት ወጥቷል፤ ውጤትዎን የሚያዩበት መንገድ

የፈተና ወረቀቶች

የ12ኛ ክፍል ፊዚክስ መግቢያ ፈተና፣ 2013 ዓ.ም. (2021)

ተማሪዎች በ2013 ዓ.ም. የተፈተኑበት የ12ኛ ክፍል የፊዚክስ የዩኒቨርሲቲ መግቢያ ፈተና እውነተኛ ጥያቄዎች። እያንዳንዱ ጥያቄ ትክክለኛ መልስ እና የተብራራ ማብራሪያ አለው።

በነጻ ልምምድ ይጀምሩየጥያቄ ወረቀት

  • የተፈጥሮ ሳይንስ ዘርፍ

    ማን ይፈተናል

  • 2013 ዓ.ም. (2021)

    የፈተና ዓመት

  • 48 ጥያቄዎች ከመልስ ጋር

    በዚህ ስብስብ

ከዚህ ፈተና ጥያቄዎችን ይሞክሩ

መልሱን ከመክፈትዎ በፊት እያንዳንዱን ጥያቄ በራስዎ ይመልሱ። ማብራሪያዎቹ ወደ መማሪያ መጽሐፉ ትክክለኛ ክፍል ይጠቁማሉ፤ ስለዚህ ጥያቄ ሲስቱ የትኛውን ገጽ እንደገና ማንበብ እንዳለብዎት ያውቃሉ።

ጥያቄ 1

According to the kinetic theory of gases, the

  1. A.particles of an ideal gas undergo inelastic collision between themselves and with the walls of the container.
  2. B.diffusion rate of a gas is inversely proportional to the square root of the molar mass because it is directly proportional to the molecular speed.
  3. C.internal energy of an ideal gas is equal to the potential energy due to interaction between the particles of the gas.
  4. D.average translational kinetic energy of the particles of an ideal gas increases as the gas gets cooled.
መልሱን እና ማብራሪያውን ይመልከቱ

መልስ፦ B diffusion rate of a gas is inversely proportional to the square root of the molar mass because it is directly proportional to the molecular speed.

ለምን

According to Graham's law, the rate of diffusion of a gas is inversely proportional to the square root of its molar mass. This is because the root-mean-square speed of the gas molecules, vrms=3RT/Mv_{rms} = \sqrt{3RT/M}, is also inversely proportional to the square root of the molar mass.

ጥያቄ 2

At t=0t = 0, an object undergoing SHM has maximum displacement of 0.650 m and angular frequency of 7.40 rad/s. Which of the following is correct about the motion of the oscillator?

  1. A.The position of the object is x=0.650cos⁡(7.40t)x = 0.650\cos(7.40t) and its acceleration is a=−35.59cos⁡(7.40t)a = -35.59\cos(7.40t).
  2. B.The frequency of the oscillator is 7.40 Hz and its period is 0.135 s.
  3. C.The position of the object is x=0.650sin⁡(7.40t)x = 0.650\sin(7.40t) and its velocity is v=4.81cos⁡(7.40t)v = 4.81\cos(7.40t).
  4. D.The position of the object is x=0.650cos⁡(7.40t)x = 0.650\cos(7.40t) and its acceleration is a=−3.59sin⁡(7.40t)a = -3.59\sin(7.40t).
መልሱን እና ማብራሪያውን ይመልከቱ

መልስ፦ A The position of the object is x=0.650cos⁡(7.40t)x = 0.650\cos(7.40t) and its acceleration is a=−35.59cos⁡(7.40t)a = -35.59\cos(7.40t).

ለምን

With maximum displacement at t=0t = 0, the position equation is x=Acos⁡(ωt)=0.650cos⁡(7.40t)x = A\cos(\omega t) = 0.650\cos(7.40t). Since acceleration is a=−ω2xa = -\omega^2 x, we have a=−(7.40)2⋅0.650cos⁡(7.40t)=−35.59cos⁡(7.40t)a = -(7.40)^2 \cdot 0.650\cos(7.40t) = -35.59\cos(7.40t).

ጥያቄ 3

A 0.35 kg mass attached to the end of a spring oscillates 2.5 times per second with amplitude of 0.15 m. Which of the following is true about the motion of the mass?

  1. A.The velocity when it is 0.10 m from equilibrium is 3.0 m/s.
  2. B.The acceleration when it is 0.10 m from equilibrium is 25.00 m/s225.00\ \mathrm{m/s^2}.
  3. C.The velocity when it passes the equilibrium is 2.355 m/s.
  4. D.The total energy of the system is 97.0 J.
መልሱን እና ማብራሪያውን ይመልከቱ

መልስ፦ C The velocity when it passes the equilibrium is 2.355 m/s.

ለምን

The maximum velocity of the mass occurs when it passes through the equilibrium position, given by vmax=Aω=A(2πf)v_{max} = A\omega = A(2\pi f). Substituting the values with π≈3.14\pi \approx 3.14, we get vmax=0.15×2×3.14×2.5=2.355 m/sv_{max} = 0.15 \times 2 \times 3.14 \times 2.5 = 2.355\text{ m/s}.

ጥያቄ 4

Identify a true statement about a mechanical wave.

  1. A.The speed of a wave traveling across a thin string is equal to its speed when traveling across a thick string of the same length and tension.
  2. B.The speed of a wave traveling along a string increases as the tension in the string increases and as the linear density of the string decreases.
  3. C.As a wave travels from one point to another along a medium, it transmits energy and particles of the medium from point to point.
  4. D.The velocity of a traveling wave is equal to the velocity of the particles through which the wave propagates.
መልሱን እና ማብራሪያውን ይመልከቱ

መልስ፦ B The speed of a wave traveling along a string increases as the tension in the string increases and as the linear density of the string decreases.

ለምን

The velocity of a transverse wave on a stretched string is given by v=T/μv = \sqrt{T/\mu}, where TT is the tension and μ\mu is the linear mass density. Therefore, the wave speed increases when tension increases or when the linear density decreases.

ጥያቄ 5

Which one of the following is a correct statement about the intensity of sound?

  1. A.It is directly proportional to the square of the distance from the sound source.
  2. B.It is inversely proportional to the square of the distance from the source of sound.
  3. C.It is the product of power of a sound and area through which the sound is transmitted
  4. D.It is energy transmitted per unit time.
መልሱን እና ማብራሪያውን ይመልከቱ

መልስ፦ B It is inversely proportional to the square of the distance from the source of sound.

ለምን

The intensity II of sound from a point source in an open space is given by I=P/(4πr2)I = P / (4\pi r^2), which is inversely proportional to the square of the distance rr from the source.

ጥያቄ 6

Which of the following is correct about Doppler effect?

  1. A.When a sound source moves away from stationary observer, the frequency detected by the observer increases, whereas the wavelength decreases.
  2. B.Doppler effect is the change in the frequency of a wave due to relative motion between the wave source and an observer.
  3. C.It is the change in the velocity of a wave due to relative motion between the source of the wave and an observer.
  4. D.When a source of sound wave moves toward stationary observer, the wavelength of the wave increases while its frequency decreases.
መልሱን እና ማብራሪያውን ይመልከቱ

መልስ፦ B Doppler effect is the change in the frequency of a wave due to relative motion between the wave source and an observer.

ለምን

The Doppler effect is defined as the change in the observed frequency of a wave due to the relative motion between the wave source and the observer.

ሙሉውን ፈተና በ PDF ያውርዱ

በዚህ ስብስብ ያሉት 48 ጥያቄዎች ሁሉ እንደ ታትሞ የወጣ ፈተና፣ የመልስ ቁልፉም ከ48 ማብራሪያዎች ጋር እንደ ሁለተኛ ፋይል። ያትሟቸው ወይም ያለ ዳታ ያንብቧቸው።

ነጻ ነው፤ መለያም አይጠይቅም።

የጥያቄ ወረቀትየመልስ ቁልፍ እና ማብራሪያዎች

ሙሉውን ፈተና በሰዓት ተገድበው ይስሩ

ነጻ የ Temari መለያ ሙሉውን የፊዚክስ ፈተና እና የሌሎች ዓመታትንም ሁሉ በሰዓት የተገደቡ የሙከራ ፈተናዎች አድርጎ ከወዲያውኑ ውጤት ጋር ይሰጥዎታል። በማንኛውም ስልክ ላይ፣ ደካማ ግንኙነት ላይም ይሰራል።

በነጻ ልምምድ ይጀምሩ

የሌሎች ዓመታት የፊዚክስ ፈተናዎች

2018 ዓ.ም. (2026)2017 ዓ.ም. (2025)2016 ዓ.ም. (2024)2015 ዓ.ም. (2023)2014 ዓ.ም. (2022)2012 ዓ.ም. (2020)2011 ዓ.ም. (2019)2010 ዓ.ም. (2018)2009 ዓ.ም. (2017)2008 ዓ.ም. (2016)2007 ዓ.ም. (2015)2006 ዓ.ም. (2014)2005 ዓ.ም. (2013)

ይህን ፈተና ከመቀመጥዎ በፊት ፊዚክስ ያጥኑ

የ12ኛ ክፍል ፊዚክስ አጭር ማስታወሻዎች 28 ካርዶች አሏቸው። እያንዳንዱ ከአገር አቀፉ መጽሐፍ ምዕራፍ በምዕራፍ ተዘጋጅቶ ሕጉን፣ ምልክቶቹ ምን እንደሚወክሉና ውጤት የሚያሳጣውን ስህተት ይናገራል።

የፊዚክስ ማስታወሻዎችን ይክፈቱ
እነዚህ እውነተኛዎቹ የ2013 ዓ.ም. የፊዚክስ መግቢያ ፈተና ጥያቄዎች ናቸው?

አዎ። ተማሪዎች በ2013 ዓ.ም. (2021) ከተፈተኑበት ብሔራዊ የዩኒቨርሲቲ መግቢያ የፊዚክስ ፈተና የተወሰዱ ናቸው። ስብስባችን ከጥያቄዎቹ 48 ያህሉን ይዟል፤ እያንዳንዱም መልስና ወደ መማሪያ መጽሐፉ የሚጠቁም ማብራሪያ አለው።

ሙሉውን ፈተና እንዴት እለማመዳለሁ?

በስልክ ቁጥር ነጻ መለያ ይክፈቱ። ሙሉው ፈተና በሰዓት የተገደበ የሙከራ ፈተና ሆኖ ወዲያውኑ ውጤት ይሰጣል፣ በወር 199 ብር የሆነው የ AI አጋዥ ማሻሻያም ያመለጠዎትን ሁሉ ያስረዳዎታል።

የ2013 ዓ.ም. የፊዚክስ ፈተናን በ PDF ማውረድ እችላለሁ?

አዎ፤ ነጻም ነው። የጥያቄ ወረቀቱ አንድ ፋይል ነው፤ የመልስ ቁልፉ ከማብራሪያዎቹ ጋር ሌላ ፋይል ነው፤ ስለዚህ ፈተናውን መጀመሪያ መሞከር ይችላሉ። ያትሟቸው፣ ወይም ዳታ በሌለበት ጊዜ ለክለሳ በስልክዎ ላይ ያስቀምጧቸው።

ይግቡመለያዎን ይክፈቱ