የ12ኛ ክፍል ውጤት ወጥቷል፤ ውጤትዎን የሚያዩበት መንገድ

የፈተና ወረቀቶች

የ12ኛ ክፍል ኬሚስትሪ መግቢያ ፈተና፣ 2009 ዓ.ም. (2017)

ተማሪዎች በ2009 ዓ.ም. የተፈተኑበት የ12ኛ ክፍል የኬሚስትሪ የዩኒቨርሲቲ መግቢያ ፈተና እውነተኛ ጥያቄዎች። እያንዳንዱ ጥያቄ ትክክለኛ መልስ እና የተብራራ ማብራሪያ አለው።

በነጻ ልምምድ ይጀምሩየጥያቄ ወረቀት

  • የተፈጥሮ ሳይንስ ዘርፍ

    ማን ይፈተናል

  • 2009 ዓ.ም. (2017)

    የፈተና ዓመት

  • 69 ጥያቄዎች ከመልስ ጋር

    በዚህ ስብስብ

ከዚህ ፈተና ጥያቄዎችን ይሞክሩ

መልሱን ከመክፈትዎ በፊት እያንዳንዱን ጥያቄ በራስዎ ይመልሱ። ማብራሪያዎቹ ወደ መማሪያ መጽሐፉ ትክክለኛ ክፍል ይጠቁማሉ፤ ስለዚህ ጥያቄ ሲስቱ የትኛውን ገጽ እንደገና ማንበብ እንዳለብዎት ያውቃሉ።

ጥያቄ 1

Which of the following covalent bonds is the most polar?

  1. A.H - F
  2. B.H - C
  3. C.H - H
  4. D.H - N
መልሱን እና ማብራሪያውን ይመልከቱ

መልስ፦ A H - F

ለምን

The polarity of a covalent bond is determined by the difference in electronegativity between the bonded atoms. The electronegativity difference is greatest between hydrogen (2.2) and fluorine (4.0), making the H-F bond the most polar.

ጥያቄ 2

The force that hold different atoms or ions together are called?

  1. A.Electric forces
  2. B.Physical bonds
  3. C.Chemical bond
  4. D.Atomic forces
መልሱን እና ማብራሪያውን ይመልከቱ

መልስ፦ C Chemical bond

ለምን

A chemical bond is the attractive force that holds atoms or ions together to create molecules or compounds.

ጥያቄ 3

How many electrons are shared between two atoms in a double bond?

  1. A.2
  2. B.3
  3. C.4
  4. D.6
መልሱን እና ማብራሪያውን ይመልከቱ

መልስ፦ C 4

ለምን

A covalent bond shares pairs of electrons; a single bond consists of 2 shared electrons, while a double bond consists of 2 pairs, which equals 4 shared electrons.

ጥያቄ 5

What is the chemical formula of the compound formed by aluminium (III) and sulphate ion, SO42−\mathrm{SO_4^{2-}} ?

  1. A.AlSO4\mathrm{AlSO_4}
  2. B.Al2SO4\mathrm{Al_2SO_4}
  3. C.Al2(SO4)3\mathrm{Al_2(SO_4)_3}
  4. D.Al(SO4)3\mathrm{Al(SO_4)_3}
መልሱን እና ማብራሪያውን ይመልከቱ

መልስ፦ C Al2(SO4)3\mathrm{Al_2(SO_4)_3}

ለምን

Aluminium forms a 3+ cation (Al³⁺) and sulfate is a 2- polyatomic anion (SO₄²⁻). To balance the charges to zero, two Al³⁺ ions combine with three SO₄²⁻ ions to give Al₂(SO₄)₃.

ጥያቄ 6

Which of the following is the most reasonable valence- bond structure of the nirocyl chloride (NOCl)? [Figure: The four options are scanned Lewis (electron-dot) structures, one per option, each drawn on a pale lilac background. Option A: ':O - N - Cl' written with capital letters; the O has a pair of dots above it, a pair of dots to its left (drawn as a colon) and a pair of dots below it, and is joined to N by a single horizontal line; the N has a pair of dots above and a pair of dots below, and is joined to Cl by a short single dash; the Cl has a pair of dots above and a pair of dots below. Option B: 'O = N - Cl'; the O has a pair of dots above and a pair of dots below and is joined to N by a double line (two parallel horizontal strokes); the N has one pair of dots above it only; N is joined to Cl by a short single dash; the Cl has a pair of dots above and a pair of dots below. Option C: ': O - N = Cl'; a pair of dots stands to the left of O, and O also has a pair of dots above and a pair of dots below; O is joined to N by a single short dash; N has a pair of dots above and a pair of dots below; N is joined to Cl by a double line; Cl has a pair of dots above and a pair of dots below. Option D: ': O = N Cl'; a pair of dots stands to the left of O and a pair of dots above it; O is joined to N by a double line; N has a pair of dots above and a pair of dots below; Cl stands with no bond line drawn to N and carries a pair of dots above and a pair of dots below. The tick marking the key sits at the end of option B's line.]

  1. A.O and N joined by a single bond, N and Cl joined by a single bond; O carries three lone pairs (above, left and below), N carries two lone pairs (above and below), Cl carries two lone pairs (above and below)
  2. B.O and N joined by a double bond, N and Cl joined by a single bond; O carries two lone pairs (above and below), N carries one lone pair (above), Cl carries two lone pairs (above and below)
  3. C.O and N joined by a single bond, N and Cl joined by a double bond; O carries three lone pairs (left, above and below), N carries two lone pairs (above and below), Cl carries two lone pairs (above and below)
  4. D.O and N joined by a double bond, no bond drawn between N and Cl; O carries two lone pairs (left and above), N carries two lone pairs (above and below), Cl carries two lone pairs (above and below)
መልሱን እና ማብራሪያውን ይመልከቱ

መልስ፦ B O and N joined by a double bond, N and Cl joined by a single bond; O carries two lone pairs (above and below), N carries one lone pair (above), Cl carries two lone pairs (above and below)

ለምን

In nitrosyl chloride (NOCl), nitrogen is the central atom bonded to oxygen via a double bond and to chlorine via a single bond (O=N-Cl), giving each atom a complete octet and minimizing formal charges.

ጥያቄ 8

Which of the following is the correct order for electrons filling in orbitals?

  1. A.3s, 3p, 4s, 3d
  2. B.2p, 3s, 3p, 3d
  3. C.3p, 4s, 3d, 5s
  4. D.4s, 3d, 4p, 4d
መልሱን እና ማብራሪያውን ይመልከቱ

መልስ፦ A 3s, 3p, 4s, 3d

ለምን

According to the Aufbau principle (the (n + l) rule), the filling order of orbitals is 3s (n+l = 3), 3p (n+l = 4), 4s (n+l = 4, lower n), and then 3d (n+l = 5).

ሙሉውን ፈተና በ PDF ያውርዱ

በዚህ ስብስብ ያሉት 69 ጥያቄዎች ሁሉ እንደ ታትሞ የወጣ ፈተና፣ የመልስ ቁልፉም ከ65 ማብራሪያዎች ጋር እንደ ሁለተኛ ፋይል። ያትሟቸው ወይም ያለ ዳታ ያንብቧቸው።

ነጻ ነው፤ መለያም አይጠይቅም።

የጥያቄ ወረቀትየመልስ ቁልፍ እና ማብራሪያዎች

ሙሉውን ፈተና በሰዓት ተገድበው ይስሩ

ነጻ የ Temari መለያ ሙሉውን የኬሚስትሪ ፈተና እና የሌሎች ዓመታትንም ሁሉ በሰዓት የተገደቡ የሙከራ ፈተናዎች አድርጎ ከወዲያውኑ ውጤት ጋር ይሰጥዎታል። በማንኛውም ስልክ ላይ፣ ደካማ ግንኙነት ላይም ይሰራል።

በነጻ ልምምድ ይጀምሩ

የሌሎች ዓመታት የኬሚስትሪ ፈተናዎች

2018 ዓ.ም. (2026)2017 ዓ.ም. (2025)2016 ዓ.ም. (2024)2015 ዓ.ም. (2023)2014 ዓ.ም. (2022)2013 ዓ.ም. (2021)2012 ዓ.ም. (2020)2011 ዓ.ም. (2019)2010 ዓ.ም. (2018)2008 ዓ.ም. (2016)2007 ዓ.ም. (2015)2006 ዓ.ም. (2014)2005 ዓ.ም. (2013)

ይህን ፈተና ከመቀመጥዎ በፊት ኬሚስትሪ ያጥኑ

የ12ኛ ክፍል ኬሚስትሪ አጭር ማስታወሻዎች 22 ካርዶች አሏቸው። እያንዳንዱ ከአገር አቀፉ መጽሐፍ ምዕራፍ በምዕራፍ ተዘጋጅቶ ሕጉን፣ ምልክቶቹ ምን እንደሚወክሉና ውጤት የሚያሳጣውን ስህተት ይናገራል።

የኬሚስትሪ ማስታወሻዎችን ይክፈቱ
እነዚህ እውነተኛዎቹ የ2009 ዓ.ም. የኬሚስትሪ መግቢያ ፈተና ጥያቄዎች ናቸው?

አዎ። ተማሪዎች በ2009 ዓ.ም. (2017) ከተፈተኑበት ብሔራዊ የዩኒቨርሲቲ መግቢያ የኬሚስትሪ ፈተና የተወሰዱ ናቸው። ስብስባችን ከጥያቄዎቹ 69 ያህሉን ይዟል፤ እያንዳንዱም መልስና ወደ መማሪያ መጽሐፉ የሚጠቁም ማብራሪያ አለው።

ሙሉውን ፈተና እንዴት እለማመዳለሁ?

በስልክ ቁጥር ነጻ መለያ ይክፈቱ። ሙሉው ፈተና በሰዓት የተገደበ የሙከራ ፈተና ሆኖ ወዲያውኑ ውጤት ይሰጣል፣ በወር 199 ብር የሆነው የ AI አጋዥ ማሻሻያም ያመለጠዎትን ሁሉ ያስረዳዎታል።

የ2009 ዓ.ም. የኬሚስትሪ ፈተናን በ PDF ማውረድ እችላለሁ?

አዎ፤ ነጻም ነው። የጥያቄ ወረቀቱ አንድ ፋይል ነው፤ የመልስ ቁልፉ ከማብራሪያዎቹ ጋር ሌላ ፋይል ነው፤ ስለዚህ ፈተናውን መጀመሪያ መሞከር ይችላሉ። ያትሟቸው፣ ወይም ዳታ በሌለበት ጊዜ ለክለሳ በስልክዎ ላይ ያስቀምጧቸው።

ይግቡመለያዎን ይክፈቱ