የ12ኛ ክፍል ውጤት ወጥቷል፤ ውጤትዎን የሚያዩበት መንገድ

የፈተና ወረቀቶች

የ12ኛ ክፍል ኬሚስትሪ መግቢያ ፈተና፣ 2013 ዓ.ም. (2021)

ተማሪዎች በ2013 ዓ.ም. የተፈተኑበት የ12ኛ ክፍል የኬሚስትሪ የዩኒቨርሲቲ መግቢያ ፈተና እውነተኛ ጥያቄዎች። እያንዳንዱ ጥያቄ ትክክለኛ መልስ እና የተብራራ ማብራሪያ አለው።

  • የተፈጥሮ ሳይንስ ዘርፍ

    ማን ይፈተናል

  • 2013 ዓ.ም. (2021)

    የፈተና ዓመት

  • 69 ጥያቄዎች ከመልስ ጋር

    በዚህ ስብስብ

ከዚህ ፈተና ጥያቄዎችን ይሞክሩ

መልሱን ከመክፈትዎ በፊት እያንዳንዱን ጥያቄ በራስዎ ይመልሱ። ማብራሪያዎቹ ወደ መማሪያ መጽሐፉ ትክክለኛ ክፍል ይጠቁማሉ፤ ስለዚህ ጥያቄ ሲስቱ የትኛውን ገጽ እንደገና ማንበብ እንዳለብዎት ያውቃሉ።

ጥያቄ 1

From the magnitude of the equilibrium constant, Keq one can deduce that

  1. A.large K eq value indicates that the reaction reaches equilibrium with very little reactants remaining.
  2. B.Small K eq values indicate the reaction yields very higher amounts of products near equilibrium.
  3. C.K eq will be larger when we have higher amounts of reactants over products.
  4. D.Intermediate K eq value indicates that the reaction does proceed in the forward direction.
መልሱን እና ማብራሪያውን ይመልከቱ

መልስ፦ A large K eq value indicates that the reaction reaches equilibrium with very little reactants remaining.

ለምን

A large equilibrium constant (Keq > 10^3) indicates that the forward reaction is highly favored, meaning that at equilibrium, the mixture consists almost entirely of products with very little reactants remaining.

ጥያቄ 2

The statement 'If a system at equilibrium is subjected to a stress, the system will readjust itself to reduce the effects of the stress' is known as

  1. A.Avogadro's principle.
  2. B.Faradays law.
  3. C.Le-Chatelier's principle.
  4. D.Boyle's law.
መልሱን እና ማብራሪያውን ይመልከቱ

መልስ፦ C Le-Chatelier's principle.

ለምን

Le-Chatelier's principle states that if a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium shifts to counteract the change to re-establish an equilibrium.

ጥያቄ 3

The law of mass action states that

  1. A.The K eq expression is the ratio of the concentrations of reactants to the products raised to their coefficients.
  2. B.The rate of a reaction is directly proportional to the product of the concentration of reactants raised to the power of their respective coefficients in the balanced equation.
  3. C.For a reaction at equilibrium, the reaction quotient, Q is always less than the equilibrium constant, Keq.
  4. D.A chemical equilibrium is attained only when the reaction is started with reactants.
መልሱን እና ማብራሪያውን ይመልከቱ

መልስ፦ B The rate of a reaction is directly proportional to the product of the concentration of reactants raised to the power of their respective coefficients in the balanced equation.

ለምን

The law of mass action states that the rate of a chemical reaction is directly proportional to the product of the concentrations of the reactants, each raised to a power equal to its stoichiometric coefficient in the balanced equation.

ጥያቄ 4

For the reaction between gaseous NO and O 2 to for NO 2 (g), what will be the equilibrium constant expression, 2NO(g) + O 2 (g)↔ 2NO 2 (g)

  1. A.K p =(P NO2 )/(P NO )(P O2 )
  2. B.K c =(NO 2 ) 2 / (NO) 2 (O 2)
  3. C.K p =(P NO2 ) 2 (P O2 ) / (P NO2 )
  4. D.K p =(P NO2 ) 2 /(NO) 2 (O 2 )
መልሱን እና ማብራሪያውን ይመልከቱ

መልስ፦ B K c =(NO 2 ) 2 / (NO) 2 (O 2)

ለምን

The equilibrium constant expression Kc is the ratio of the molar concentrations of products to reactants, each raised to the power of their stoichiometric coefficients. Thus, for 2NO(g) + O2(g) ⇌ 2NO2(g), Kc = [NO2]^2 / ([NO]^2 * [O2]).

ጥያቄ 5

The equilibrium constant K p for the reaction 2SO 2 (g) ⇌ 2SO 3 (g) + O 2 (g) is 3.8 × 10 -3 K p at 227 °C. What is the value of K c for the reaction at the same temperature?

  1. A.4.6 × 10 -4 mol m -3
  2. B.1.8 × 10 -3 mol m -3
  3. C.2.3 × 10 -4 mol m -3
  4. D.9.1 × 10 -4 mol m -3
መልሱን እና ማብራሪያውን ይመልከቱ

መልስ፦ D 9.1 × 10 -4 mol m -3

ለምን

For the reaction 2SO3(g) ⇌ 2SO2(g) + O2(g), the change in moles of gas is Δn = 1. Using Kc = Kp / (RT) with T = 500 K and R = 0.08206 L atm/(mol K) yields approximately 9.1 * 10^-5 mol/L (often misprinted with different exponents or units as 9.1 * 10^-4 mol m^-3).

ጥያቄ 6

In the Galvanic cell given in the diagram below Identify the component parts correctly labelled for the letters a, b, c, d and choose the correct one among the following a, b, c, and d , respectively

  1. A.Copper anode, Zinc cathode, voltmeter , salt bridge
  2. B.Zinc cathode, Copper cathode, Zinc anode, Copper cathode
  3. C.Copper anode, Zinc anode, CuSO 4 (sol), voltmeter
  4. D.Zinc anode, Copper cathode, ZnSO 4 (sol), salt bridge
መልሱን እና ማብራሪያውን ይመልከቱ

መልስ፦ D Zinc anode, Copper cathode, ZnSO 4 (sol), salt bridge

ለምን

In a standard Daniell (Galvanic) cell, zinc acts as the anode, copper as the cathode, zinc sulfate and copper sulfate as the electrolyte solutions, and a salt bridge connects the two half-cells.

ሙሉውን ፈተና በ PDF ያውርዱ

በዚህ ስብስብ ያሉት 69 ጥያቄዎች ሁሉ እንደ ታትሞ የወጣ ፈተና፣ የመልስ ቁልፉም ከ69 ማብራሪያዎች ጋር እንደ ሁለተኛ ፋይል። ያትሟቸው ወይም ያለ ዳታ ያንብቧቸው።

ነጻ ነው፤ መለያም አይጠይቅም።

ሙሉውን ፈተና በሰዓት ተገድበው ይስሩ

ነጻ የ Temari መለያ ሙሉውን የኬሚስትሪ ፈተና እና የሌሎች ዓመታትንም ሁሉ በሰዓት የተገደቡ የሙከራ ፈተናዎች አድርጎ ከወዲያውኑ ውጤት ጋር ይሰጥዎታል። በማንኛውም ስልክ ላይ፣ ደካማ ግንኙነት ላይም ይሰራል።

በነጻ ልምምድ ይጀምሩ

ይህን ፈተና ከመቀመጥዎ በፊት ኬሚስትሪ ያጥኑ

የ12ኛ ክፍል ኬሚስትሪ አጭር ማስታወሻዎች 22 ካርዶች አሏቸው። እያንዳንዱ ከአገር አቀፉ መጽሐፍ ምዕራፍ በምዕራፍ ተዘጋጅቶ ሕጉን፣ ምልክቶቹ ምን እንደሚወክሉና ውጤት የሚያሳጣውን ስህተት ይናገራል።

የኬሚስትሪ ማስታወሻዎችን ይክፈቱ
እነዚህ እውነተኛዎቹ የ2013 ዓ.ም. የኬሚስትሪ መግቢያ ፈተና ጥያቄዎች ናቸው?

አዎ። ተማሪዎች በ2013 ዓ.ም. (2021) ከተፈተኑበት ብሔራዊ የዩኒቨርሲቲ መግቢያ የኬሚስትሪ ፈተና የተወሰዱ ናቸው። ስብስባችን ከጥያቄዎቹ 69 ያህሉን ይዟል፤ እያንዳንዱም መልስና ወደ መማሪያ መጽሐፉ የሚጠቁም ማብራሪያ አለው።

ሙሉውን ፈተና እንዴት እለማመዳለሁ?

በስልክ ቁጥር ነጻ መለያ ይክፈቱ። ሙሉው ፈተና በሰዓት የተገደበ የሙከራ ፈተና ሆኖ ወዲያውኑ ውጤት ይሰጣል፣ በወር 199 ብር የሆነው የ AI አጋዥ ማሻሻያም ያመለጠዎትን ሁሉ ያስረዳዎታል።

የ2013 ዓ.ም. የኬሚስትሪ ፈተናን በ PDF ማውረድ እችላለሁ?

አዎ፤ ነጻም ነው። የጥያቄ ወረቀቱ አንድ ፋይል ነው፤ የመልስ ቁልፉ ከማብራሪያዎቹ ጋር ሌላ ፋይል ነው፤ ስለዚህ ፈተናውን መጀመሪያ መሞከር ይችላሉ። ያትሟቸው፣ ወይም ዳታ በሌለበት ጊዜ ለክለሳ በስልክዎ ላይ ያስቀምጧቸው።

ይግቡመለያዎን ይክፈቱ