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Qormaata galuumsa kutaa 12ffaa Fiiziksii, bara 2010 A.L.I (2018)

Gaaffilee dhugaa qormaata galuumsa yunivarsiitii kutaa 12 kan Fiiziksii, akkuma barattoonni bara 2010 A.L.I itti fudhatanitti. Tokkoon tokkoon gaaffii deebii sirrii fi ibsa qaba.

  • Damee saayinsii uumamaa

    Eenyutu fudhata

  • 2010 A.L.I (2018)

    Bara qormaataa

  • Gaaffilee 41 deebii waliin

    Kuusaa kana keessa

Gaaffilee qormaata kanaa yaalaa

Deebii banuun dura tokkoon tokkoon gaaffii ofii keessaniin deebisaa. Ibsi gara kutaa kitaaba barnootaa sirriitti waan qajeelchuuf, yeroo gaaffii dogoggortan fuula kam irra deebi'uu akka qabdan ni beektu.

Gaaffii 1

Four vectors are listed below A⃗=[410]\vec{A} = \begin{bmatrix} 4 \\ 10 \end{bmatrix}. B⃗=[2−5]\vec{B} = \begin{bmatrix} 2 \\ -5 \end{bmatrix}, C⃗=[−615]\vec{C} = \begin{bmatrix} -6 \\ 15 \end{bmatrix}, D⃗=[15−6]\vec{D} = \begin{bmatrix} 15 \\ -6 \end{bmatrix}, Which pair of the vectors is orthogonal?

  1. A.A⃗\vec{A} and D⃗\vec{D}
  2. B.B⃗\vec{B} and C⃗\vec{C}
  3. C.C⃗\vec{C} and D⃗\vec{D}
  4. D.A⃗\vec{A} and B⃗\vec{B}
Deebii fi ibsa ilaalaa

Deebii: A A⃗\vec{A} and D⃗\vec{D}

Maaliif

Two vectors are orthogonal if their dot product equals zero. Calculating the dot product for A⃗\vec{A} and D⃗\vec{D} gives (4)(15)+(10)(−6)=60−60=0(4)(15) + (10)(-6) = 60 - 60 = 0, so they are orthogonal.

Gaaffii 2

A race car is moving at a constant speed of 35m/s . A security car was moving at a speed of 5m/s as the race car passes by it and was accelerating at constant rate of 5 m/s2\mathrm{m/s^2}. What was the speed of the security car when it took over the race car ?

  1. A.35m/s
  2. B.60m/s
  3. C.5m/s
  4. D.65m/s
Deebii fi ibsa ilaalaa

Deebii: D 65m/s

Maaliif

Equating the positions of the race car and security car: 35t=5t+12(5)t235t = 5t + \frac{1}{2}(5)t^2, which simplifies to 2.5t2=30t2.5t^2 = 30t, giving t=12 st = 12\text{ s}. The final speed of the security car is v=v0+at=5+5(12)=65 m/sv = v_0 + at = 5 + 5(12) = 65\text{ m/s}.

Gaaffii 3

A car start moving from rest and its motion on a straight line is shown in the figure below. What is the average velocity of the car within the first 6 seconds? [Figure: Hand-drawn velocity-time graph. Vertical axis labelled v (m/s) with tick marks at 2, 4, 6, 8, 10 and 12; horizontal axis labelled t(s) with tick marks at 2, 4, 6 and 8. The trace consists of three straight segments: a line rising from the origin to a point labelled "2, 6" (t = 2 s, v = 6 m/s); a horizontal segment from that point to a point labelled "4, 6" (t = 4 s, v = 6 m/s); then a line rising from there to a point labelled "6, 10" (t = 6 s, v = 10 m/s), where the trace ends.]

  1. A.5.67m/s
  2. B.1.67 m/s
  3. C.5 m/s
  4. D.6 m/s
Deebii fi ibsa ilaalaa

Deebii: A 5.67m/s

Maaliif

The total displacement is the area under the v-tv\text{-}t graph: Area 1 is 12(2)(6)=6 m\frac{1}{2}(2)(6) = 6\text{ m}, Area 2 is (4−2)(6)=12 m(4-2)(6) = 12\text{ m}, and Area 3 is 6+102(6−4)=16 m\frac{6+10}{2}(6-4) = 16\text{ m}, giving a total of 34 m34\text{ m}. Dividing by the total time of 6 s6\text{ s} yields an average velocity of 346≈5.67 m/s\frac{34}{6} \approx 5.67\text{ m/s}.

Gaaffii 4

Which one of the following statements is correct regarding the motion in a plane?

  1. A.When a body moves in a horizontal circle, its velocity is constant
  2. B.When a body moves in a vertical circle, its speed is constant
  3. C.The centripetal force for a body moving in either vertical or horizontal circle is toward the center
  4. D.In projectile motion the horizontal component of the motion is uniformly accelerated motion.
Deebii fi ibsa ilaalaa

Deebii: C The centripetal force for a body moving in either vertical or horizontal circle is toward the center

Maaliif

By definition, the centripetal force is always directed toward the center of the circular trajectory for any circular motion. Option A is incorrect because the velocity vector continuously changes direction even if speed is constant.

Gaaffii 5

A bullet is fired at an angel of 30° above the horizontal. If air resistance is neglected, what should be the bullet's horizontal acceleration (ax⃗)(\vec{a_x}) and vertical acceleration (ay⃗)(\vec{a_y}) when it reaches its maximum height?

  1. A.Both ax⃗\vec{a_x} and ay⃗\vec{a_y} are zero
  2. B.ax⃗\vec{a_x} is 10 m/s2\mathrm{m/s^2} downward, and ay⃗\vec{a_y} is zero
  3. C.Both ax⃗\vec{a_x} and ay⃗\vec{a_y} are 10 m/s2\mathrm{m/s^2} downward
  4. D.ax⃗\vec{a_x} is zero, and ay⃗\vec{a_y} is 10 m/s2\mathrm{m/s^2} downward.
Deebii fi ibsa ilaalaa

Deebii: D ax⃗\vec{a_x} is zero, and ay⃗\vec{a_y} is 10 m/s2\mathrm{m/s^2} downward.

Maaliif

In standard projectile motion neglecting air resistance, gravity acts solely downward with an acceleration of approximately 10 m/s210\text{ m/s}^2, while there is no force in the horizontal direction, so ax=0a_x = 0 throughout the flight.

Gaaffii 6

Two students A and B, with masses mAm_A and mBm_B respectively, stand on a wheeled trolleys as shown in the figure below. If student A has larger mass and pushes student B, then what can be said about their accelerations? [Figure: Line drawing of two boys facing each other, each standing on a small four-wheeled trolley (skateboard-like platform) resting on a hatched horizontal ground line. The boy on the left is labelled A, the boy on the right is labelled B. A leans forward with both arms extended, his hands pressing against B's hands, so A is pushing B to the right. Both boys are drawn about the same size; no forces or numerical values are marked.]

  1. A.The acceleration of student B is less than that of student A.
  2. B.Both boys will be accelerated by the same magnitude but in opposite directions.
  3. C.The acceleration of student A is less than that of student B.
  4. D.There would be no acceleration because the forcec are equal and opposite.
Deebii fi ibsa ilaalaa

Deebii: C The acceleration of student A is less than that of student B.

Maaliif

According to Newton's third law, the forces exerted on both students are equal in magnitude and opposite in direction. Since acceleration is inversely proportional to mass (a=F/ma = F/m), the heavier student A experiences a smaller acceleration than student B.

Qormaata guutuu PDF dhaan buufadhaa

Gaaffilee 41 kuusaa kana keessa jiran hunda akka waraqaa qormaataa maxxanfameetti, furtuu deebii ibsa 39 waliin immoo akka faayilii lammaffaatti. Maxxansaa yookiin daataa malee dubbisaa.

Bilisa; herregas hin gaafatu.

Qormaata guutuu sa'aatiin daangeffamee hojjedhaa

Herregni Temari bilisaa qormaata Fiiziksii guutuu fi kan waggoota biroo hunda qormaatilee fakkeenyaa sa'aatiin daangeffaman godhee qabxii battalumaa waliin isiniif kenna. Bilbila kamiyyuu irratti, walitti hidhamiinsa laafaa irrattillee ni hojjeta.

Bilisaan shaakaluu jalqabaa

Qormaata kana taa'uu dura Fiiziksii qayyabadhu

Yaadannoon gabaabaan Fiiziksii kutaa 12 kaardii 28 qaba. Tokkoon tokkoon boqonnaa boqonnaadhaan kitaaba biyyaalessaa irraa qophaa'ee seericha, mallattoowwan isaa maal bakka akka bu'an fi dogoggora qabxii nama dhabsiisu ni ibsa.

Yaadannoo Fiiziksii bani
Kunneen gaaffilee dhugaa qormaata galuumsa Fiiziksii bara 2010 A.L.I ti?

Eeyyee. Qormaata galuumsa yunivarsiitii biyyaalessaa kan Fiiziksii barattoonni bara 2010 A.L.I (2018) fudhatan irraa fudhataman. Kuusaan keenya gaaffilee isaa 41 qaba; tokkoon tokkoon isaanii deebii fi ibsa gara kitaaba barnootaatti qajeelchu qabu.

Qormaata guutuu akkamittan shaakala?

Lakkoofsa bilbilaatiin herrega bilisaa banadhaa. Qormaatichi guutuun qormaata fakkeenyaa sa'aatiin daangeffame ta'ee qabxii battalumaa kenna; fooyya'iinsi gargaaraa AI ji'atti qarshii 199 kan ta'e waan isin jalaa darbe hunda isinii ibsa.

Qormaata Fiiziksii bara 2010 A.L.I PDF dhaan buufachuu nan danda'aa?

Eeyyee; bilisas. Waraqaan gaaffii faayilii tokko, furtuun deebii ibsa isaa waliin immoo faayilii biraa ti; kanaaf qormaata dursitanii yaaluu dandeessu. Maxxansaa, yookiin yeroo daataan hin jirre irra deebiif bilbila keessan irratti kaa'adhaa.

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