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Waraqaalee qormaataa

Qormaata galuumsa kutaa 12ffaa Fiiziksii, bara 2011 A.L.I (2019)

Gaaffilee dhugaa qormaata galuumsa yunivarsiitii kutaa 12 kan Fiiziksii, akkuma barattoonni bara 2011 A.L.I itti fudhatanitti. Tokkoon tokkoon gaaffii deebii sirrii fi ibsa qaba.

  • Damee saayinsii uumamaa

    Eenyutu fudhata

  • 2011 A.L.I (2019)

    Bara qormaataa

  • Gaaffilee 45 deebii waliin

    Kuusaa kana keessa

Gaaffilee qormaata kanaa yaalaa

Deebii banuun dura tokkoon tokkoon gaaffii ofii keessaniin deebisaa. Ibsi gara kutaa kitaaba barnootaa sirriitti waan qajeelchuuf, yeroo gaaffii dogoggortan fuula kam irra deebi'uu akka qabdan ni beektu.

Gaaffii 2

Which part of a scientific report discusses the accuracy of measurements taken?

  1. A.Aim
  2. B.Theory
  3. C.Methods
  4. D.Results
Deebii fi ibsa ilaalaa

Deebii: D Results

Maaliif

The 'Results' section of a scientific report contains the recorded data, calculations of averages, and the analysis of experimental uncertainties and errors, which directly discuss the accuracy of the measurements.

Gaaffii 3

Two forces exerted on a block as shown in the figure below. What is the horizontal component of the net force? [Figure: A rectangular block is shown. From its top-left corner, a force vector of magnitude 50 N is directed upward and to the left, making an angle of 53° with the horizontal line extending to the left. From its top-right corner, a force vector of magnitude 20 N is directed upward and to the right, making an angle of 37° with the horizontal line extending to the right.]

  1. A.70 N, East
  2. B.30 N, West
  3. C.14 N, West
  4. D.28 N, West
Deebii fi ibsa ilaalaa

Deebii: C 14 N, West

Maaliif

The horizontal component of the net force is calculated by subtracting the westward horizontal component of the 50 N force from the eastward horizontal component of the 20 N force: F_net,x = 20*cos(37°) - 50*cos(53°) = 20(0.8) - 50(0.6) = 16 - 30 = -14 N, which represents 14 N to the West.

Gaaffii 4

What is the magnitude of the resultant velocity for a bird flying first at a speed of 10 m/s North East and then flying to South at a speed of 8 m/s?

  1. A.7,13 m/s
  2. B.16.6 m/s
  3. C.12.8 m/s
  4. D.7.07 m/s
Deebii fi ibsa ilaalaa

Deebii: A 7,13 m/s

Maaliif

Resolving the velocities into components, we have v_1 = (10*cos(45°), 10*sin(45°)) = (7.07, 7.07) m/s and v_2 = (0, -8) m/s. The resultant velocity is v = (7.07, -0.93) m/s, which has a magnitude of sqrt(7.07^2 + (-0.93)^2) ≈ 7.13 m/s.

Gaaffii 5

Let C⃗=A⃗XB⃗\vec{C}=\vec{A}\text{X}\vec{B} and θ≠900\theta \neq 90^0, where θ\theta is the smaller angle between A⃗\vec{A} and B⃗\vec{B} when they are drawn with their tails at the same point. Which of the following is NOT true?

  1. A.A⃗.B⃗=0\vec{A}.\vec{B} = 0
  2. B.A⃗.C⃗=0\vec{A}.\vec{C} = 0
  3. C./C⃗/=/A⃗//B⃗/sin⁡θ/\vec{C}/=/\vec{A}//\vec{B}/ \sin \theta
  4. D.−C⃗=B⃗XA⃗-\vec{C}=\vec{B}\text{X}\vec{A}
Deebii fi ibsa ilaalaa

Deebii: A A⃗.B⃗=0\vec{A}.\vec{B} = 0

Maaliif

The dot product of two vectors is given by A.B = |A||B|cosθ. Since θ ≠ 90°, the dot product cannot be zero, making option A the only incorrect statement.

Gaaffii 6

A driver of an automobile travelling at a constant speed of 20 m/s suddenly applies a brake and the automobile comes to rest in 2.0 seconds after skidding for a certain distance. What is the length of the skid distance?

  1. A.400 m
  2. B.10 m
  3. C.40 m
  4. D.20 m
Deebii fi ibsa ilaalaa

Deebii: D 20 m

Maaliif

Using the kinematic formula for constant acceleration, the skid distance is d = ((v_0 + v)/2)*t = ((20 + 0)/2)*2.0 = 20 m.

Gaaffii 7

Which of the following is correct about the motion shown in the velocity – time graph below? [Figure: A velocity-time graph showing velocity v(m/s) on the vertical axis and time t(Sec) on the horizontal axis. - Vertical axis has markings from 2 to 14 in increments of 2. - Horizontal axis has markings A, 2, 4, 6, 8, 10, 12, 14. - A straight line starts at the origin A(0,0) and rises to point B(2,4), with dashed lines indicating t = 2 and v = 4. - From B(2,4), a steeper straight line rises to point C(3,12), with a dashed horizontal line extending to v = 12. - From C(3,12), a horizontal line segment connects to point D(6,12). - From D(6,12), a straight line descends to point E(12,0) on the horizontal axis.]

  1. A.Between C and D, the motion is with constant acceleration.
  2. B.Between B and C, the acceleration is 4m/s24\text{m/s}^2
  3. C.Between D and E, the motion is with constant positive acceleration.
  4. D.Total displacement is 84m.
Deebii fi ibsa ilaalaa

Deebii: D Total displacement is 84m.

Maaliif

The total displacement is the area under the velocity-time graph, which consists of four sections: Area = 0.5*2*4 + 0.5*(4+12)*1 + 3*12 + 0.5*6*12 = 4 + 8 + 36 + 36 = 84 m.

Qormaata guutuu PDF dhaan buufadhaa

Gaaffilee 45 kuusaa kana keessa jiran hunda akka waraqaa qormaataa maxxanfameetti, furtuu deebii ibsa 45 waliin immoo akka faayilii lammaffaatti. Maxxansaa yookiin daataa malee dubbisaa.

Bilisa; herregas hin gaafatu.

Qormaata guutuu sa'aatiin daangeffamee hojjedhaa

Herregni Temari bilisaa qormaata Fiiziksii guutuu fi kan waggoota biroo hunda qormaatilee fakkeenyaa sa'aatiin daangeffaman godhee qabxii battalumaa waliin isiniif kenna. Bilbila kamiyyuu irratti, walitti hidhamiinsa laafaa irrattillee ni hojjeta.

Bilisaan shaakaluu jalqabaa

Qormaata kana taa'uu dura Fiiziksii qayyabadhu

Yaadannoon gabaabaan Fiiziksii kutaa 12 kaardii 28 qaba. Tokkoon tokkoon boqonnaa boqonnaadhaan kitaaba biyyaalessaa irraa qophaa'ee seericha, mallattoowwan isaa maal bakka akka bu'an fi dogoggora qabxii nama dhabsiisu ni ibsa.

Yaadannoo Fiiziksii bani
Kunneen gaaffilee dhugaa qormaata galuumsa Fiiziksii bara 2011 A.L.I ti?

Eeyyee. Qormaata galuumsa yunivarsiitii biyyaalessaa kan Fiiziksii barattoonni bara 2011 A.L.I (2019) fudhatan irraa fudhataman. Kuusaan keenya gaaffilee isaa 45 qaba; tokkoon tokkoon isaanii deebii fi ibsa gara kitaaba barnootaatti qajeelchu qabu.

Qormaata guutuu akkamittan shaakala?

Lakkoofsa bilbilaatiin herrega bilisaa banadhaa. Qormaatichi guutuun qormaata fakkeenyaa sa'aatiin daangeffame ta'ee qabxii battalumaa kenna; fooyya'iinsi gargaaraa AI ji'atti qarshii 199 kan ta'e waan isin jalaa darbe hunda isinii ibsa.

Qormaata Fiiziksii bara 2011 A.L.I PDF dhaan buufachuu nan danda'aa?

Eeyyee; bilisas. Waraqaan gaaffii faayilii tokko, furtuun deebii ibsa isaa waliin immoo faayilii biraa ti; kanaaf qormaata dursitanii yaaluu dandeessu. Maxxansaa, yookiin yeroo daataan hin jirre irra deebiif bilbila keessan irratti kaa'adhaa.

SeeniHerrega kee bani