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Waraqaalee qormaataa

Qormaata ministirii kutaa 8ffaa Herregaa, bara 2015 A.L.I (2023)

Gaaffilee dhugaa qormaata ministirii kutaa 8ffaa kan Herregaa, akkuma barattoonni bara 2015 A.L.I itti fudhatanitti. Tokkoon tokkoon gaaffii deebii sirrii fi ibsa qaba.

Bilisaan shaakaluu jalqabaaWaraqaa gaaffii

  • Barattoota kutaa 8ffaa hunda

    Eenyutu fudhata

  • 2015 A.L.I (2023)

    Bara qormaataa

  • Gaaffilee 40 deebii waliin

    Kuusaa kana keessa

Gaaffilee qormaata kanaa yaalaa

Deebii banuun dura tokkoon tokkoon gaaffii ofii keessaniin deebisaa. Ibsi gara kutaa kitaaba barnootaa sirriitti waan qajeelchuuf, yeroo gaaffii dogoggortan fuula kam irra deebi'uu akka qabdan ni beektu.

Gaaffii 1

The number 3153\frac{1}{5} as a single fraction is equal to

  1. A.165\frac{16}{5}
  2. B.45\frac{4}{5}
  3. C.145\frac{14}{5}
  4. D.95\frac{9}{5}
Deebii fi ibsa ilaalaa

Deebii: A 165\frac{16}{5}

Maaliif

To convert the mixed fraction 3153\frac{1}{5} to an improper fraction, multiply the whole number by the denominator and add the numerator: 3×5+15=165\frac{3 \times 5 + 1}{5} = \frac{16}{5}.

Gaaffii 2

|-\frac{2}{3}| + \frac{1}{3} is equal to

  1. A.13\frac{1}{3}
  2. B.23\frac{2}{3}
  3. C.1
  4. D.-1
Deebii fi ibsa ilaalaa

Deebii: C 1

Maaliif

The absolute value of −23-\frac{2}{3} is 23\frac{2}{3}. Adding 13\frac{1}{3} results in 23+13=33=1\frac{2}{3} + \frac{1}{3} = \frac{3}{3} = 1.

Gaaffii 3

Which one of the following is true?

  1. A.12<35<710\frac{1}{2} < \frac{3}{5} < \frac{7}{10}
  2. B.710<35<12\frac{7}{10} < \frac{3}{5} < \frac{1}{2}
  3. C.12<710<35\frac{1}{2} < \frac{7}{10} < \frac{3}{5}
  4. D.35<710<12\frac{3}{5} < \frac{7}{10} < \frac{1}{2}
Deebii fi ibsa ilaalaa

Deebii: A 12<35<710\frac{1}{2} < \frac{3}{5} < \frac{7}{10}

Maaliif

Converting each fraction to a decimal gives 12=0.5\frac{1}{2} = 0.5, 35=0.6\frac{3}{5} = 0.6, and 710=0.7\frac{7}{10} = 0.7. Since 0.5<0.6<0.70.5 < 0.6 < 0.7, the statement 12<35<710\frac{1}{2} < \frac{3}{5} < \frac{7}{10} is true.

Gaaffii 4

\frac{3}{7} + \frac{1}{2} =

  1. A.514\frac{5}{14}
  2. B.49\frac{4}{9}
  3. C.27\frac{2}{7}
  4. D.1314\frac{13}{14}
Deebii fi ibsa ilaalaa

Deebii: D 1314\frac{13}{14}

Maaliif

To add the fractions, find a common denominator, which is 14. This yields 3×214+1×714=6+714=1314\frac{3 \times 2}{14} + \frac{1 \times 7}{14} = \frac{6 + 7}{14} = \frac{13}{14}.

Gaaffii 5

The sum of two rational numbers is 3. If one of the numbers is 94\frac{9}{4}, then the other number is

  1. A.34\frac{3}{4}
  2. B.214\frac{21}{4}
  3. C.12\frac{1}{2}
  4. D.23\frac{2}{3}
Deebii fi ibsa ilaalaa

Deebii: A 34\frac{3}{4}

Maaliif

Subtract the given rational number from the total sum: 3−94=124−94=343 - \frac{9}{4} = \frac{12}{4} - \frac{9}{4} = \frac{3}{4}.

Gaaffii 6

(−34)×(−109)=\left(-\frac{3}{4}\right) \times \left(-\frac{10}{9}\right) =

  1. A.2740\frac{27}{40}
  2. B.56\frac{5}{6}
  3. C.−2740-\frac{27}{40}
  4. D.−56-\frac{5}{6}
Deebii fi ibsa ilaalaa

Deebii: B 56\frac{5}{6}

Maaliif

The product of two negative numbers is positive. Multiplying the fractions gives 3×104×9=3036\frac{3 \times 10}{4 \times 9} = \frac{30}{36}, which simplifies to 56\frac{5}{6} by dividing both the numerator and denominator by 6.

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