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Grade 8 Mathematics ministry exam, 2015 E.C. (2023)

Real questions from the Grade 8 ministry exam in Mathematics, as students sat it in 2015 E.C. Every question comes with the correct answer and a worked explanation.

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  • Every Grade 8 student

    Who sits it

  • 2015 E.C. (2023)

    Exam year

  • 40 questions with answers

    In this set

Try questions from this paper

Answer each question yourself before opening the answer. The explanations point to the exact place in the textbook, so you know which page to reread when you miss one.

Question 1

The number 3153\frac{1}{5} as a single fraction is equal to

  1. A.165\frac{16}{5}
  2. B.45\frac{4}{5}
  3. C.145\frac{14}{5}
  4. D.95\frac{9}{5}
Show the answer and explanation

Answer: A 165\frac{16}{5}

Why

To convert the mixed fraction 3153\frac{1}{5} to an improper fraction, multiply the whole number by the denominator and add the numerator: 3×5+15=165\frac{3 \times 5 + 1}{5} = \frac{16}{5}.

Question 2

|-\frac{2}{3}| + \frac{1}{3} is equal to

  1. A.13\frac{1}{3}
  2. B.23\frac{2}{3}
  3. C.1
  4. D.-1
Show the answer and explanation

Answer: C 1

Why

The absolute value of −23-\frac{2}{3} is 23\frac{2}{3}. Adding 13\frac{1}{3} results in 23+13=33=1\frac{2}{3} + \frac{1}{3} = \frac{3}{3} = 1.

Question 3

Which one of the following is true?

  1. A.12<35<710\frac{1}{2} < \frac{3}{5} < \frac{7}{10}
  2. B.710<35<12\frac{7}{10} < \frac{3}{5} < \frac{1}{2}
  3. C.12<710<35\frac{1}{2} < \frac{7}{10} < \frac{3}{5}
  4. D.35<710<12\frac{3}{5} < \frac{7}{10} < \frac{1}{2}
Show the answer and explanation

Answer: A 12<35<710\frac{1}{2} < \frac{3}{5} < \frac{7}{10}

Why

Converting each fraction to a decimal gives 12=0.5\frac{1}{2} = 0.5, 35=0.6\frac{3}{5} = 0.6, and 710=0.7\frac{7}{10} = 0.7. Since 0.5<0.6<0.70.5 < 0.6 < 0.7, the statement 12<35<710\frac{1}{2} < \frac{3}{5} < \frac{7}{10} is true.

Question 4

\frac{3}{7} + \frac{1}{2} =

  1. A.514\frac{5}{14}
  2. B.49\frac{4}{9}
  3. C.27\frac{2}{7}
  4. D.1314\frac{13}{14}
Show the answer and explanation

Answer: D 1314\frac{13}{14}

Why

To add the fractions, find a common denominator, which is 14. This yields 3×214+1×714=6+714=1314\frac{3 \times 2}{14} + \frac{1 \times 7}{14} = \frac{6 + 7}{14} = \frac{13}{14}.

Question 5

The sum of two rational numbers is 3. If one of the numbers is 94\frac{9}{4}, then the other number is

  1. A.34\frac{3}{4}
  2. B.214\frac{21}{4}
  3. C.12\frac{1}{2}
  4. D.23\frac{2}{3}
Show the answer and explanation

Answer: A 34\frac{3}{4}

Why

Subtract the given rational number from the total sum: 3−94=124−94=343 - \frac{9}{4} = \frac{12}{4} - \frac{9}{4} = \frac{3}{4}.

Question 6

(−34)×(−109)=\left(-\frac{3}{4}\right) \times \left(-\frac{10}{9}\right) =

  1. A.2740\frac{27}{40}
  2. B.56\frac{5}{6}
  3. C.−2740-\frac{27}{40}
  4. D.−56-\frac{5}{6}
Show the answer and explanation

Answer: B 56\frac{5}{6}

Why

The product of two negative numbers is positive. Multiplying the fractions gives 3×104×9=3036\frac{3 \times 10}{4 \times 9} = \frac{30}{36}, which simplifies to 56\frac{5}{6} by dividing both the numerator and denominator by 6.

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Mathematics papers from other years

2017 E.C. model exam2016 E.C. model exam2012 E.C. model exam

Revise Mathematics before you sit this paper

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Are these real Grade 8 Mathematics ministry exam questions?

Yes. They come from the Grade 8 Mathematics ministry exam that students sat in 2015 E.C. (2023). Our set holds 40 of its questions, each with its answer and a worked explanation.

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Can I download the Mathematics 2015 E.C. paper as a PDF?

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