Bu'aan kutaa 12ffaa ba'eera; bu'aa kee eessatti akka ilaaltu

Yaadannoo boqonnaa fi gaaffii shaakalaa

Boqonnaa 4 Keemistirii kutaa 11: Kaayineetiksii Keemikaalaa

Wanti fuula kana irra jiru hundi boqonnaa 4 kitaaba Keemistirii kutaa 11 tiif: wanta boqonnaan haguugu, yaadannoo gabaabaa, gaaffii shaakalaa deebii isaanii waliin, fi viidiyoo barnootaa bakka jirutti.

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3
Kaardii
10
Gaaffii shaakalaa boqonnaa 4
193–221
Fuula kitaabaa boqonnaa 4

Boqonnaan 4 maal haguuga

  1. 1.The Rate of a Reaction
  2. 2.Factors Affecting the Rate of a Chemical Reaction

Yaadannoo gabaabaa boqonnaa 4

Kaardiiwwan fuula Keemistirii kutaa 11 irratti boqonnaa kana jala galmaa'an. Tokko tokkoon bani.

Yoom akka itti fayyadamtu

Walitti bu'iinsi molakiyuulotaa maaliif oomisha akka kennu yookiin akka hin kennine ibsuuf gargaara.

Of eeggadhu

Walnyaatinsi akka raawwatuuf ulaagaaleen lamaan guutamuu qabu: kallattii sirrii fi anniisaa activation energy wajjin walqixa yookiin caalu qabaachuu qabu.

Grade 11 Chemistry, fuula 193-221 irraa qophaa'e; osoo hin ba'in dura yeroo lama mirkanaa'e

Rate=−1aΔ[A]Δt=−1bΔ[B]Δt=1cΔ[C]Δt=1dΔ[D]Δt\text{Rate} = -\frac{1}{a}\frac{\Delta [\text{A}]}{\Delta t} = -\frac{1}{b}\frac{\Delta [\text{B}]}{\Delta t} = \frac{1}{c}\frac{\Delta [\text{C}]}{\Delta t} = \frac{1}{d}\frac{\Delta [\text{D}]}{\Delta t}
Rate\text{Rate}
Saffisa walnyaatinsaamol L−1s−1\text{mol}\,\text{L}^{-1}\text{s}^{-1}
Δ[A]\Delta [\text{A}]
Jijjiirama concentration reektantii Amol L−1\text{mol}\,\text{L}^{-1}
Δt\Delta t
Garaagarummaa yeroos\text{s}
aa
Koofishentii istookiyomeetrikii reektantii A11

Yoom akka itti fayyadamtu

Reetii walnyaatinsaa dhabama reektantootaa yookiin uumama oomishootaa wajjin walqabsiisuuf itti fayyadamaa.

Of eeggadhu

Yeroo hunda jijjiirama concentration tokkoon tokkoo wantootaa koofishentii isaaniitiif qooduu qabdu.

Grade 11 Chemistry, fuula 193-221 irraa qophaa'e; osoo hin ba'in dura yeroo lama mirkanaa'e

Yoom akka itti fayyadamtu

Reetii walnyaatinsaa dhabama reektantootaan yeroo ibsinutti itti fayyadamna.

Of eeggadhu

Concentration reektantootaa waan hir'atuuf jijjiiramni isaa negative ta'a. Reetiin walnyaatinsaa positive akka ta'uuf mallattoon negative dura kaa'amuu qaba.

Grade 11 Chemistry, fuula 193-221 irraa qophaa'e; osoo hin ba'in dura yeroo lama mirkanaa'e

Gaaffii shaakalaa boqonnaa 4

Gaaffii filannoo 10 boqonnaa kana irratti barreeffaman, tokkoon tokkoon isaanii deebii fi sababa qabu. Deebii banuu dura yaali. Gaaffiin kun Ingiliffaa tiin.

Gaaffii 1

The rate of a chemical reaction is best defined as:

  1. A.the total mass of products formed at the end of the reaction
  2. B.the change in concentration of a reactant or product per unit time
  3. C.the temperature at which the reaction starts
  4. D.the number of moles of catalyst used in the reaction
Deebii fi sababa agarsiisi

Deebii: B the change in concentration of a reactant or product per unit time

Sababa

The chapter says the rate of a chemical reaction measures the change in concentration of a reactant or a product per unit time. Mass at the end, starting temperature and amount of catalyst are not the definition.

Gaaffii 2

Why does increasing the temperature of a reaction mixture usually increase the rate of reaction?

  1. A.The average kinetic energy of the reacting particles increases, so they collide more frequently and with greater energy.
  2. B.The activation energy of the reaction increases.
  3. C.The reactant concentration increases as the mixture is heated.
  4. D.The reaction stops being a chemical change.
Deebii fi sababa agarsiisi

Deebii: A The average kinetic energy of the reacting particles increases, so they collide more frequently and with greater energy.

Sababa

The chapter explains that when temperature rises, the average kinetic energy of the particles increases. This makes the particles collide more often and with more energy, so the rate goes up.

Gaaffii 3

Why do finely divided solids react more rapidly than the same mass of the same substance in a large lump?

  1. A.The lump has more activation energy than the powder.
  2. B.The powder contains a catalyst.
  3. C.The powder has a greater surface area available for the reaction.
  4. D.The lump absorbs more heat from the air.
Deebii fi sababa agarsiisi

Deebii: C The powder has a greater surface area available for the reaction.

Sababa

The chapter says finely divided solids react more rapidly because of the greater surface area available. More surface means more particles are exposed to the other reactant at one time.

Gaaffii 4

Which statement about a positive catalyst is correct?

  1. A.It raises the activation energy, so the reaction becomes slower.
  2. B.It is used up completely by the reaction.
  3. C.It lowers the activation energy, so the reaction becomes faster.
  4. D.It changes the position of equilibrium.
Deebii fi sababa agarsiisi

Deebii: C It lowers the activation energy, so the reaction becomes faster.

Sababa

The chapter says a positive catalyst increases the rate of reaction by lowering the activation energy, Ea. Catalysts are not used up and do not change the position of equilibrium.

Gaaffii 5

For the reaction 3O2(g) → 2O3(g), which rate expression is correct?

  1. A.Rate = -Δ[O<sub>2</sub>]/Δt = Δ[O<sub>3</sub>]/Δt
  2. B.Rate = -(1/3)Δ[O<sub>2</sub>]/Δt = (1/2)Δ[O<sub>3</sub>]/Δt
  3. C.Rate = -(1/2)Δ[O<sub>2</sub>]/Δt = (1/3)Δ[O<sub>3</sub>]/Δt
  4. D.Rate = -(1/3)Δ[O<sub>3</sub>]/Δt = (1/2)Δ[O<sub>2</sub>]/Δt
Deebii fi sababa agarsiisi

Deebii: B Rate = -(1/3)Δ[O<sub>2</sub>]/Δt = (1/2)Δ[O<sub>3</sub>]/Δt

Sababa

The coefficients are 3 for O2 and 2 for O3. Each reactant term is divided by its coefficient (1/3 for O2), and each product term is divided by its coefficient (1/2 for O3). A minus sign is used for the reactant because its concentration decreases.

Gaaffii 6

In the reaction 2NO(g) + 2H2(g) → N2(g) + 2H2O(g), the rate of disappearance of NO is 4.0 × 10-5 mol L-1 s-1. What is the rate of formation of N2?

  1. A.4.0 × 10<sup>-5</sup> mol L<sup>-1</sup> s<sup>-1</sup>
  2. B.1.0 × 10<sup>-5</sup> mol L<sup>-1</sup> s<sup>-1</sup>
  3. C.2.0 × 10<sup>-5</sup> mol L<sup>-1</sup> s<sup>-1</sup>
  4. D.8.0 × 10<sup>-5</sup> mol L<sup>-1</sup> s<sup>-1</sup>
Deebii fi sababa agarsiisi

Deebii: C 2.0 × 10<sup>-5</sup> mol L<sup>-1</sup> s<sup>-1</sup>

Sababa

NO has a coefficient of 2 and N2 has a coefficient of 1. So the rate of N2 formation equals (1/2) of the rate of NO disappearance: (1/2) × 4.0 × 10-5 = 2.0 × 10-5 mol L-1 s-1.

Gaaffii 7

For the decomposition 2N2O5(g) → 4NO2(g) + O2(g), the average rate of formation of NO2 between 300 s and 400 s is 4.8 × 10-5 mol L-1 s-1. What is the average rate of formation of O2 in the same period?

  1. A.2.4 × 10<sup>-5</sup> mol L<sup>-1</sup> s<sup>-1</sup>
  2. B.4.8 × 10<sup>-5</sup> mol L<sup>-1</sup> s<sup>-1</sup>
  3. C.1.9 × 10<sup>-4</sup> mol L<sup>-1</sup> s<sup>-1</sup>
  4. D.1.2 × 10<sup>-5</sup> mol L<sup>-1</sup> s<sup>-1</sup>
Deebii fi sababa agarsiisi

Deebii: D 1.2 × 10<sup>-5</sup> mol L<sup>-1</sup> s<sup>-1</sup>

Sababa

The coefficients of NO2 and O2 are 4 and 1. The chapter says the rate of NO2 formation is four times the rate of O2 formation. So the rate of O2 formation is 4.8 × 10-5 ÷ 4 = 1.2 × 10-5 mol L-1 s-1.

Gaaffii 8

A student in a laboratory in Addis Ababa puts marble chips and dilute HCl in a flask on a balance. The mass of the flask and its contents goes down during the reaction. Why does the mass decrease?

  1. A.The HCl evaporates from the flask.
  2. B.The marble chips dissolve completely into the water.
  3. C.Carbon dioxide gas escapes from the flask.
  4. D.The flask absorbs water from the air.
Deebii fi sababa agarsiisi

Deebii: C Carbon dioxide gas escapes from the flask.

Sababa

In this experiment the reaction produces carbon dioxide gas. The gas leaves the flask, so the total mass in the flask goes down. The decrease in mass is used to measure the rate of reaction.

Gaaffii 9

For the reaction 4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g), at a certain moment O2 is reacting at 0.050 mol L-1 s-1. At what rate is H2O being formed?

  1. A.0.040 mol L<sup>-1</sup> s<sup>-1</sup>
  2. B.0.050 mol L<sup>-1</sup> s<sup>-1</sup>
  3. C.0.060 mol L<sup>-1</sup> s<sup>-1</sup>
  4. D.0.075 mol L<sup>-1</sup> s<sup>-1</sup>
Deebii fi sababa agarsiisi

Deebii: C 0.060 mol L<sup>-1</sup> s<sup>-1</sup>

Sababa

Rate = -(1/5)Δ[O2]/Δt = (1/6)Δ[H2O]/Δt. So Δ[H2O]/Δt = (6/5) × 0.050 = 0.060 mol L-1 s-1. Water has the bigger coefficient, so it forms faster than O2 is used up.

Gaaffii 10

Which rate expression is correct for the reaction 5Br-(aq) + BrO3-(aq) + 6H+(aq) → 3Br2(aq) + 3H2O(l)?

  1. A.Rate = -(1/5)Δ[Br<sup>-</sup>]/Δt = -(1/6)Δ[H<sup>+</sup>]/Δt
  2. B.Rate = -Δ[Br<sup>-</sup>]/Δt = -6Δ[H<sup>+</sup>]/Δt
  3. C.Rate = -(1/6)Δ[Br<sup>-</sup>]/Δt = -(1/5)Δ[H<sup>+</sup>]/Δt
  4. D.Rate = -6Δ[H<sup>+</sup>]/Δt
Deebii fi sababa agarsiisi

Deebii: A Rate = -(1/5)Δ[Br<sup>-</sup>]/Δt = -(1/6)Δ[H<sup>+</sup>]/Δt

Sababa

Each reactant term is divided by its own coefficient. Br- has a coefficient of 5 and H+ has a coefficient of 6. A minus sign is used for reactants because their concentrations decrease.

Appiin boqonnaa kana irratti gaaffii 12 qaba; utuu hojjettuu ni sirreessa. Kan asii jiran 10 jalqabaa ti.

Fuula kitaabaa boqonnaa 4

Boqonnaan 4 Maxxansa Ministeera Barnootaa keessatti fuula 193 hanga fuula 221 ti.

Maxxansa Ministeera Barnootaa, Ingiliffaa, Fuula 342

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