Bu'aan kutaa 12ffaa ba'eera; bu'aa kee eessatti akka ilaaltu

Yaadannoo boqonnaa fi gaaffii shaakalaa

Boqonnaa 7 Fiizikii kutaa 11: Nuclear Physics

Wanti fuula kana irra jiru hundi boqonnaa 7 kitaaba Fiizikii kutaa 11 tiif: wanta boqonnaan haguugu, yaadannoo gabaabaa, gaaffii shaakalaa deebii isaanii waliin, fi viidiyoo barnootaa bakka jirutti.

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Gaaffii shaakalaa boqonnaa 7

Yaadannoo gabaabaa boqonnaa 7

Kaardiiwwan fuula Fiizikii kutaa 11 irratti boqonnaa kana jala galmaa'an. Tokko tokkoon bani.

Gosa kubbaaQaamolee baasanJijjiirama AJijjiirama Z
α\alpha24He^{4}_{2}\mathrm{He}−4-4−2-2
β−\beta^{-}−10e^{0}_{-1}\mathrm{e}00+1+1
β+\beta^{+}+10e^{0}_{+1}\mathrm{e}00−1-1

Yoom akka itti fayyadamtu

Yeroo equation kubbaa barreessitu ykn nuukleasii intala nuukleasii haadhaa irraa argattu fayyadamaa.

Of eeggadhu

Beta- Z tokkoon ol guddisa, A garuu hin jijjiiru; neutroon gara protoonii fi elektiroonii jijjiirama. Beta+ Z tokkoon hir'isa. Kubbaa betaa keessatti A hin jijjiirin.

Grade 11 Physics, fuula 287 irraa eegalee irraa qophaa'e; osoo hin ba'in dura yeroo lama mirkanaa'e

Yoom akka itti fayyadamtu

Humna walitti hidhamuu waliigalaa booda, humna nuukleyoonii tokkoo yeroo gaafatamu fayyadamaa.

Of eeggadhu

Lakkoofsa baay'ina nuukleyoonii A irratti qoodi, lakkoofsa atoomii Z irratti hin qoodin. Oksijiin-16 irratti 16 qoodi, 8 utuu hin taane. Fakkeenya 7.2 118.808 MeV gara 16 qooda.

Grade 11 Physics, fuula 287 irraa eegalee irraa qophaa'e; osoo hin ba'in dura yeroo lama mirkanaa'e

N=N0e−λtN=N_0 e^{-\lambda t}
NN
baay'ina nuukleyoonii yeroo t keessatti hin kubbaan11
N0N_0
baay'ina nuukleyoonii yeroo t = 0 keessatti hin kubbaan11
λ\lambda
faayidaa kubbaa, carraa kubbaa yeroo tokkoos−1\mathrm{s}^{-1}
tt
yeroo darbes\mathrm{s}

Yoom akka itti fayyadamtu

Yeroo baay'inni nuukleyoonii jalqabaa fi faayidaan kubbaa ykn yeroo walakkaa kennamee, lakkoofsi hafu yeroo t booda akkam akka ta'u gaafatamu fayyadamaa.

Of eeggadhu

λ s^-1 waan ta'eef t sekondii ta'uu qaba; waggoota jijjiiraa. Yeroo walakkaa t_{1/2} = 0.693/λ dha; yeroo nuukleyoonii walakkaan kubbaan, yeroo jiraachuu nuukleasii miti.

Grade 11 Physics, fuula 287 irraa eegalee irraa qophaa'e; osoo hin ba'in dura yeroo lama mirkanaa'e

Gaaffii shaakalaa boqonnaa 7

Gaaffii filannoo 10 boqonnaa kana irratti barreeffaman, tokkoon tokkoon isaanii deebii fi sababa qabu. Deebii banuu dura yaali. Gaaffiin kun Ingiliffaa tiin.

Gaaffii 1

According to the textbook, which subatomic particles make up the atomic nucleus?

  1. A.Protons and neutrons
  2. B.Protons and electrons
  3. C.Neutrons and electrons
  4. D.Electrons and positrons
Deebii fi sababa agarsiisi

Deebii: A Protons and neutrons

Sababa

The atomic nucleus consists of positively charged protons and electrically neutral neutrons held together by the strong nuclear force.

Gaaffii 2

What is the empirical formula used to calculate the radius R of a nucleus with mass number A?

  1. A.R = R0 A^3
  2. B.R = R0 A^2
  3. C.R = R0 A^(1/3)
  4. D.R = R0 / A^(1/3)
Deebii fi sababa agarsiisi

Deebii: C R = R0 A^(1/3)

Sababa

The nuclear radius is given by R = R0 A1/3, where R0 is approximately 1.2 fm (1.2 × 10-15 m).

Gaaffii 3

Which statement correctly defines isotopes of an element?

  1. A.Atoms with the same number of neutrons but different numbers of protons
  2. B.Atoms with the same number of protons but different numbers of neutrons
  3. C.Atoms with different atomic numbers and identical mass numbers
  4. D.Atoms that possess completely different chemical properties
Deebii fi sababa agarsiisi

Deebii: B Atoms with the same number of protons but different numbers of neutrons

Sababa

Isotopes are members of a family of an element that have the same number of protons (same atomic number) but different numbers of neutrons.

Gaaffii 4

According to the textbook, how many megaelectron volts (MeV) are equivalent to 1 atomic energy unit (aeu)?

  1. A.1.602 MeV
  2. B.100.0 MeV
  3. C.200.0 MeV
  4. D.931.1 MeV
Deebii fi sababa agarsiisi

Deebii: D 931.1 MeV

Sababa

The text states directly that 1 aeu = c2 × 1 amu = 931.1 MeV.

Gaaffii 5

At a range of 10-15 m, approximately how many times stronger is the strong nuclear force compared to electromagnetism?

  1. A.10 times
  2. B.100 times
  3. C.1,000,000 times
  4. D.10^38 times
Deebii fi sababa agarsiisi

Deebii: B 100 times

Sababa

At a range of 10-15 m, the strong force is roughly 100 times as strong as electromagnetism, 106 times as strong as the weak force, and 1038 times as strong as gravitation.

Gaaffii 6

Which teaching hospital in Addis Ababa is highlighted in the textbook for using radioisotopes to treat cancer?

  1. A.Black Lion Specialized Hospital
  2. B.St. Paul Hospital
  3. C.Yekatit 12 Hospital
  4. D.Ras Desta Damtew Hospital
Deebii fi sababa agarsiisi

Deebii: A Black Lion Specialized Hospital

Sababa

The textbook specifically notes that the Black Lion Specialized Hospital under Addis Ababa University uses radioisotopes for cancer treatment.

Gaaffii 7

When uranium-238 undergoes alpha decay, it emits an alpha particle (42He). What are the mass number A and atomic number Z of the daughter thorium (Th) nucleus?

  1. A.A = 238, Z = 90
  2. B.A = 234, Z = 91
  3. C.A = 234, Z = 90
  4. D.A = 242, Z = 94
Deebii fi sababa agarsiisi

Deebii: C A = 234, Z = 90

Sababa

In alpha decay, the mass number decreases by 4 (238 - 4 = 234) and the atomic number decreases by 2 (92 - 2 = 90), giving 23490Th.

Gaaffii 8

A sample contains 400 mg of strontium-90 (half-life = 38.1 years). How many milligrams remain after 190.5 years (5 half-lives)?

  1. A.50.0 mg
  2. B.25.0 mg
  3. C.6.25 mg
  4. D.12.5 mg
Deebii fi sababa agarsiisi

Deebii: D 12.5 mg

Sababa

After 5 half-lives (190.5 / 38.1 = 5), the remaining mass is 400 mg / (25) = 400 mg / 32 = 12.5 mg.

Gaaffii 9

Two nuclei have mass numbers in the ratio 27 : 125. What is the ratio of their nuclear radii?

  1. A.9 : 25
  2. B.3 : 5
  3. C.27 : 125
  4. D.1 : 5
Deebii fi sababa agarsiisi

Deebii: B 3 : 5

Sababa

Because R is proportional to A1/3, the ratio of the radii is (27)1/3 : (125)1/3 = 3 : 5.

Gaaffii 10

In the fission reaction 235U + 10n → XY + 139Cs + 2 10n + energy, what is the mass number X?

  1. A.95
  2. B.94
  3. C.96
  4. D.93
Deebii fi sababa agarsiisi

Deebii: A 95

Sababa

Balancing mass numbers: 235 + 1 = X + 139 + (2 × 1), which gives 236 = X + 141, so X = 95 (corresponding to Rb-95).

Appiin boqonnaa kana irratti gaaffii 12 qaba; utuu hojjettuu ni sirreessa. Kan asii jiran 10 jalqabaa ti.

Fuula kitaabaa boqonnaa 7

Kitaaba barataa Fiizikii kutaa 11 guutuu, PDF bilisaan.

Maxxansa Ministeera Barnootaa, Ingiliffaa, Fuula 338

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