Yaadannoo boqonnaa fi gaaffii shaakalaa

Boqonnaa 3 Fiizikii kutaa 11: Sochii Dimensiyoona Tokkoo fi Lama

Wanti fuula kana irra jiru hundi boqonnaa 3 kitaaba Fiizikii kutaa 11 tiif: wanta boqonnaan haguugu, yaadannoo gabaabaa, gaaffii shaakalaa deebii isaanii waliin, fi viidiyoo barnootaa bakka jirutti.

4
Kaardii: 10
Gaaffii shaakalaa boqonnaa 3: 47–94
Fuula kitaabaa boqonnaa 3

Yaadannoo gabaabaa boqonnaa 3

Kaardiiwwan fuula Fiizikii kutaa 11 irratti boqonnaa kana jala galmaa'an. Tokko tokkoon bani.

Mallattoo ariitii fi hir'inaDogoggora baratame

Yoom akka itti fayyadamtu

Yeroo gaaffiin meeshi socho'u saffisaan dabalaa jiraa moo hir'ataa jiraa jedhu gaafatu yookaan ariitii mallattoo hir'achaa kennamu yoo jiraate fayyadami.

Of eeggadhu

Ariitiin mallattoo hir'achaa hunda hir'ina jechuu miti. Saffisni fi ariitiin mallattoo wal fakkaatu yoo qabaatan meeshi saffisaan dabalaa jira; mallattoo garaagar yoo qabaatan hir'ataa jira.

Grade 11 Physics, fuula 47-94 irraa qophaa'e; osoo hin ba'in dura yeroo lama mirkanaa'e

Ariitii giddu-galeessaa sochii tuqaa keessattiFoormulaa

a_c = \frac{v^2}{r}

a_c = \frac{v^2}{r}

$a_c$: ariitii giddu-galeessaa, gara giddu-galeessaatti kan qajeelu $m\,s^{-2}$
$v$: saffisa sararaa $m\,s^{-1}$
$r$: raadiasii tuqaa $m$

Yoom akka itti fayyadamtu

Yeroo meeshi tuqaa irratti saffisa wal-qixa qabuun yoo socho'u, gara giddu-galeessaatti ariitii barbaaddan walaloo kana fayyadami.

Of eeggadhu

Raadiasii diameter isaa catuu keessaa fudhadhu. Km/sa gara m/s jijjiiruuf 3.6n qoodi; fkn 50.4 km/sa = 14 m/s.

Grade 11 Physics, fuula 47-94 irraa qophaa'e; osoo hin ba'in dura yeroo lama mirkanaa'e

Walaloo sochii ariitii tasgabaaGabatee wabiiv_f = v_i + at · s = (v_i + v_f)/2 t · s = v_i t + 1/2at^2 · +2

Walaloo	Hanga dhabamu
$v_f = v_i + at$	$s$
$s = \frac{v_i + v_f}{2}\,t$	$a$
$s = v_i t + \frac{1}{2}at^2$	$v_f$
$s = v_f t - \frac{1}{2}at^2$	$v_i$
$v_f^2 = v_i^2 + 2as$	$t$

Yoom akka itti fayyadamtu

Yeroo sochii sarara irratti ariitiin tasgabaa taatee buufata, saffisa, ariitii yookaan yeroo barbaaddan walaloo kana fayyadami. Hanga hin barbaachisne hin qabne walaloo filadhu.

Of eeggadhu

Walaloon kun yeroo ariitiin tasgabaa taatu qofa hojjeta. Ariitiin yoo jijjiiramu hin hojjetu.

Grade 11 Physics, fuula 47-94 irraa qophaa'e; osoo hin ba'in dura yeroo lama mirkanaa'e

Walaloo jijjiirama saffisaaFoormulaa

v_f = v_i + at

v_f = v_i + at

$v_f$: saffisa dhumaa $m\,s^{-1}$
$v_i$: saffisa jalqabaa $m\,s^{-1}$
$a$: ariitii tasgabaa $m\,s^{-2}$
$t$: yeroo $s$

Yoom akka itti fayyadamtu

Yeroo ariitiin tasgabaa taatee fi saffisa dhumaa yeroo t booda barbaaddan walaloo kana fayyadami.

Of eeggadhu

Saffisni fi ariitiin vektarota dha. Dura kallattii ol tokko filadhu, booda hangi hundaa mallattoo isaa kennaa. Walaloo kana ariitiin tasgabaa yeroo qofa fayyadami.

Grade 11 Physics, fuula 47-94 irraa qophaa'e; osoo hin ba'in dura yeroo lama mirkanaa'e

Gaaffii shaakalaa boqonnaa 3

Gaaffii filannoo 10 boqonnaa kana irratti barreeffaman, tokkoon tokkoon isaanii deebii fi sababa qabu. Deebii banuu dura yaali. Gaaffiin kun Ingiliffaa tiin.

Gaaffii 1

According to kinematics, what is acceleration?

A.The rate of change of velocity with time
B.The total distance divided by total time
C.The displacement per unit time in a fixed direction
D.The product of velocity and time elapsed

Deebii fi sababa agarsiisi

Deebii: A The rate of change of velocity with time

Sababa

Acceleration is defined as the rate of change of velocity with respect to time. It is a vector quantity measured in m/s².

Gaaffii 2

In a displacement versus time graph, what does the slope of the line represent?

A.Acceleration
B.Velocity
C.Total distance
D.Centripetal force

Deebii fi sababa agarsiisi

Deebii: B Velocity

Sababa

The slope of a displacement-time graph is the vertical change (displacement) divided by horizontal change (time), which equals velocity.

Gaaffii 3

What is meant by the terminal velocity of a falling body?

A.The velocity when an object starts to fall from rest
B.The maximum velocity of a freely falling body where its acceleration becomes zero
C.The minimum speed required to escape the Earth gravitational field
D.The average velocity of a projectile at maximum height

Deebii fi sababa agarsiisi

Deebii: B The maximum velocity of a freely falling body where its acceleration becomes zero

Sababa

Terminal velocity is the constant maximum velocity reached by a falling object when the upward drag force equals the downward force of gravity, so acceleration is zero.

Gaaffii 4

An object moves at a constant speed in a circular path. What is the direction of its centripetal acceleration?

A.Along the tangent in the direction of motion
B.Away from the center of the circle
C.Always towards the center of the circle
D.Opposite to the direction of velocity

Deebii fi sababa agarsiisi

Deebii: C Always towards the center of the circle

Sababa

Centripetal acceleration is caused by the continuous change in the direction of velocity and is always directed towards the center of the circular path.

Gaaffii 5

A car in Hawassa accelerates uniformly from rest to a speed of 72 km/h (20 m/s) in 8.0 seconds. What is the magnitude of its acceleration?

A.1.25 m/s2
B.2.5 m/s2
C.5.0 m/s2
D.9.0 m/s2

Deebii fi sababa agarsiisi

Deebii: B 2.5 m/s2

Sababa

Using the kinematic formula a = (v_f - v_i) / t: with v_i = 0, v_f = 20 m/s, and t = 8.0 s, we get a = 20 / 8.0 = 2.5 m/s².

Gaaffii 6

An Ethiopian Airlines Boeing airplane lands on a runway at Bole International Airport with an initial velocity of 40.0 m/s and decelerates uniformly at 1.50 m/s². What length of runway does it need to come to a complete stop?

A.266.7 m
B.400.0 m
C.533.3 m
D.600.0 m

Deebii fi sababa agarsiisi

Deebii: C 533.3 m

Sababa

Using v_f² = v_i² + 2as: here v_f = 0, v_i = 40.0 m/s, and a = -1.50 m/s². Thus, 0 = (40.0)² + 2(-1.50)s, which gives s = 1600 / 3.0 = 533.3 m.

Gaaffii 7

A wheel has a diameter of 60 cm. If its angular velocity is 40 rad/s, what is the tangential velocity at the rim of the wheel?

A.6 m/s
B.12 m/s
C.24 m/s
D.120 m/s

Deebii fi sababa agarsiisi

Deebii: B 12 m/s

Sababa

The radius is half of the diameter: r = 60 cm / 2 = 30 cm = 0.3 m. Using v_t = ωr, we get v_t = 40 rad/s × 0.3 m = 12 m/s.

Gaaffii 8

What physical quantity is represented by the area between a velocity versus time graph curve and the time axis?

A.Acceleration
B.Displacement
C.Instantaneous speed
D.Time interval

Deebii fi sababa agarsiisi

Deebii: B Displacement

Sababa

The area under a velocity-time graph line and the time axis gives the magnitude of the displacement covered by the moving body during that time interval.

Gaaffii 9

A particle moves along a straight line with its velocity given by v(t) = t² - 2t (in m/s). What is the instantaneous acceleration of the particle at t = 2 s?

A.0 m/s2
B.2 m/s2
C.4 m/s2
D.6 m/s2

Deebii fi sababa agarsiisi

Deebii: B 2 m/s2

Sababa

The functional form of acceleration is the time derivative of velocity: a(t) = 2t - 2. Evaluating at t = 2 s gives a(2) = 2(2) - 2 = 2 m/s².

Gaaffii 10

A ball is projected vertically upwards with an initial velocity of 20 m/s from the top of a building. Taking g = 10 m/s², how much time does it take to return to its initial release level?

A.2 s
B.4 s
C.5 s
D.8 s

Deebii fi sababa agarsiisi

Deebii: B 4 s

Sababa

At the starting level, the vertical displacement is y = 0. Using y = v₀t - (1/2)gt², we have 0 = 20t - 5t², which factors into 5t(4 - t) = 0. Thus, the time to return is t = 4 s.

Appiin boqonnaa kana irratti gaaffii 12 qaba; utuu hojjettuu ni sirreessa. Kan asii jiran 10 jalqabaa ti.

Fuula kitaabaa boqonnaa 3

Boqonnaan 3 Maxxansa Ministeera Barnootaa keessatti fuula 47 hanga fuula 94 ti.

Maxxansa Ministeera Barnootaa, Ingiliffaa, Fuula 338

PDF buufadhaa

Yaadannoo gabaabaa Fiizikii kutaa 11 hunda

Boqonnaa kana appii keessatti shaakali

Temari boqonnaa kana gara shaakala yeroon daangeffametti jijjiira; utuu hojjettuu ni sirreessa; wanti si hin galinis barsiisaa AI tiin ni ibsama.

Bilisaan jalqabi

Temari.et appii Android qaba; Google Play irratti bilisaan argama.

Waa'ee appii Temari