Yaadannoo boqonnaa fi gaaffii shaakalaa
Wanti fuula kana irra jiru hundi boqonnaa 4 kitaaba Herrega kutaa 9 tiif: wanta boqonnaan haguugu, yaadannoo gabaabaa, gaaffii shaakalaa deebii isaanii waliin, fi viidiyoo barnootaa bakka jirutti.
Kaardiiwwan fuula Herrega kutaa 9 irratti boqonnaa kana jala galmaa'an. Tokko tokkoon bani.
Yoom akka itti fayyadamtu
Walsimbiroo dhabuu sararaawaa gatii cimaa of keessaa qabu furuuf fayyadami.
Of eeggadhu
Gatii cimaa isa mallattoo irra caalaa qabu gara qooda lamaatti osoo hin baasin akka tokkootti furuun dogoggora fida.
Grade 9 Mathematics, fuula 130-161 irraa qophaa'e; osoo hin ba'in dura yeroo lama mirkanaa'e
Yoom akka itti fayyadamtu
Dirree furmaata walsimbiroo dhabuu sararaawaa diriira koordinetii irratti argachuuf fayyadami.
Of eeggadhu
Qabxii qormaatichaa sarara daangaa irratti filachuun gama isa kam akka halluu dibdu hin beeksisu.
Grade 9 Mathematics, fuula 130-161 irraa qophaa'e; osoo hin ba'in dura yeroo lama mirkanaa'e
| Garaagarummaa | Walsimbiroo dhabuu | Qabxiiwwan Daangaa |
|---|---|---|
| Open dots at and | ||
| Solid dots at and | ||
| Open dot at , solid dot at | ||
| Solid dot at , open dot at |
Yoom akka itti fayyadamtu
Tuuta furmaata walsimbiroo dhabuu sarara lakkoofsaa irratti yookiin bifa garaagarummaatiin ibsuuf fayyadami.
Of eeggadhu
Walsimbiroo dhabuu jabaa hin taaneef qabxii banaa fayyadamuun qabxii daangaa sirrii dhabsiisa.
Grade 9 Mathematics, fuula 130-161 irraa qophaa'e; osoo hin ba'in dura yeroo lama mirkanaa'e
Yoom akka itti fayyadamtu
Gara lamaan walsimbiroo dhabuu lakkoofsa negatiiviin yeroo baayiftu yookiin hirtu fayyadami.
Of eeggadhu
Lakkoofsa negatiiviin yeroo baayiftu yookiin hirtu mallattoo walsimbiroo dhabuu garagalchuu dhiisuun deebii dogoggoraa kenna.
Grade 9 Mathematics, fuula 130-161 irraa qophaa'e; osoo hin ba'in dura yeroo lama mirkanaa'e
Yoom akka itti fayyadamtu
Walsimbiroo dhabuu kooridiraatikii bifa baayataan jiru zeeroo irra caaluu yookiin xiqqaachuu isaa furuuf fayyadami.
Of eeggadhu
Baayataan negatiivii yeroo ta'u lameen isaaniiyyuu mallattoo waloo qabu jedhanii yaaduun dogoggora. Mallattoo faallaa qabaachuu qabu.
Grade 9 Mathematics, fuula 130-161 irraa qophaa'e; osoo hin ba'in dura yeroo lama mirkanaa'e
Gaaffii filannoo 10 boqonnaa kana irratti barreeffaman, tokkoon tokkoon isaanii deebii fi sababa qabu. Deebii banuu dura yaali. Gaaffiin kun Ingiliffaa tiin.
Gaaffii 1
According to the properties of inequalities, if a > b and m < 0, which of the following is true?
Deebii: B ma < mb
Sababa
When both sides of an inequality are multiplied or divided by a negative number, the direction of the inequality sign is reversed. Since m < 0, multiplying a > b by m gives ma < mb.
Gaaffii 2
Which interval notation represents the set of all real numbers x such that -3 ≤ x < 2?
Deebii: C [-3, 2)
Sababa
A square bracket is used for included endpoints (≤ or ≥) and a round parenthesis is used for excluded endpoints (< or >). Therefore, -3 ≤ x < 2 is written as [-3, 2).
Gaaffii 3
What is the solution set of the absolute value inequality |6x + 8| > -2?
Deebii: D All real numbers
Sababa
The absolute value of any real number is always non-negative (greater than or equal to 0). Since 0 is always greater than -2, the inequality holds true for all real numbers.
Gaaffii 4
Solve the linear inequality 3x - 9 > 7x - 1.
Deebii: B x < -2
Sababa
Subtract 7x from both sides: -4x - 9 > -1. Add 9 to both sides: -4x > 8. Dividing both sides by -4 reverses the inequality symbol, giving x < -2.
Gaaffii 5
What is the solution of the absolute value inequality |x + 2| < 4?
Deebii: A -6 < x < 2
Sababa
Using the theorem for |k| < c, we write -4 < x + 2 < 4. Subtracting 2 from all parts gives -4 - 2 < x < 4 - 2, which simplifies to -6 < x < 2.
Gaaffii 6
What is the solution in interval notation for the quadratic inequality (x - 3)(x - 1) < 0?
Deebii: B (1, 3)
Sababa
For the product of two factors to be negative, one factor must be positive and the other negative. This occurs when x - 1 > 0 and x - 3 < 0, which gives 1 < x < 3, or the interval (1, 3).
Gaaffii 7
What is the solution to the absolute value inequality |-5x - 7| ≤ 0?
Deebii: D x = -7/5
Sababa
An absolute value cannot be strictly less than 0, so the inequality only holds when |-5x - 7| = 0. Solving -5x - 7 = 0 gives -5x = 7, so x = -7/5.
Gaaffii 8
What is the solution set of the quadratic inequality x2 - x ≥ 12?
Deebii: C (-infinity, -3] U [4, infinity)
Sababa
Rewrite as x2 - x - 12 ≥ 0 and factor to get (x - 4)(x + 3) ≥ 0. The product is non-negative when x ≤ -3 or x ≥ 4, which is (-∞, -3] ∪ [4, ∞).
Gaaffii 9
Kebede has saved 6,000 birr for a tractor. He plans to save 1,000 birr each month until his total savings are more than 80,000 birr. If m is the number of months, which inequality and solution represent his saving plan?
Deebii: A 6,000 + 1,000m > 80,000; m > 74
Sababa
Kebede starts with 6,000 birr and adds 1,000m birr. To have more than 80,000 birr: 6,000 + 1,000m > 80,000. Subtracting 6,000 gives 1,000m > 74,000, so m > 74.
Gaaffii 10
Chaltu has 50 birr in her phone account. She is charged 0.20 birr for each text message. If her total bill can be at most 80 birr, what is the maximum number of text messages she can send?
Deebii: B 150
Sababa
At most means less than or equal to: 0.2m + 50 ≤ 80. Subtracting 50 gives 0.2m ≤ 30. Dividing by 0.2 gives m ≤ 150, so she can send a maximum of 150 messages.
Barnoota boqonnaa kanaa YouTube irraa. Yommuu play tuqxu qofa fe'ama.
Compound inequalities: Linear inequalities (part 2) · YouTube irratti ilaali
Boqonnaan 4 Maxxansa Ministeera Barnootaa keessatti fuula 130 hanga fuula 161 ti.
Maxxansa Ministeera Barnootaa, Ingiliffaa, Fuula 337
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