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Qormaata galuumsa kutaa 12ffaa Herregaa, bara 2013 A.L.I (2021), maxxansa 1

Gaaffilee dhugaa qormaata galuumsa yunivarsiitii kutaa 12 kan Herregaa, akkuma barattoonni bara 2013 A.L.I itti fudhatanitti. Tokkoon tokkoon gaaffii deebii sirrii fi ibsa qaba. Qormaanni bara 2013 A.L.I maxxansa adda addaatiin bahe. Fuulli kun maxxansa 1 qaba; kaan gadi aanee tarreeffamaniiru.

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  • 2013 A.L.I (2021), maxxansa 1

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  • Gaaffilee 36 deebii waliin

    Kuusaa kana keessa

Gaaffilee qormaata kanaa yaalaa

Deebii banuun dura tokkoon tokkoon gaaffii ofii keessaniin deebisaa. Ibsi gara kutaa kitaaba barnootaa sirriitti waan qajeelchuuf, yeroo gaaffii dogoggortan fuula kam irra deebi'uu akka qabdan ni beektu.

Gaaffii 1

Let a function f(x) = -4x^3 - 2x - 10, then which one of the following is true about f.

  1. A.f is neither even nor odd
  2. B.f is odd
  3. C.f is even
  4. D.f is both even and odd
Deebii fi ibsa ilaalaa

Deebii: A f is neither even nor odd

Maaliif

A function is even if f(-x) = f(x) and odd if f(-x) = -f(x). For f(x) = -4x^3 - 2x - 10, we have f(-x) = 4x^3 + 2x - 10, which is neither equal to f(x) nor to -f(x).

Gaaffii 2

If (g o f)(x) = x^2 + x + 6 and f(x) = x + 2, then what is the equivalent expression for g(x)?

  1. A.x^2 - 3x + 8
  2. B.-x^2 - 3x + 6
  3. C.x^2 + 3x + 8
  4. D.x^2 - 3x - 6
Deebii fi ibsa ilaalaa

Deebii: A x^2 - 3x + 8

Maaliif

Letting y = f(x) = x + 2 gives x = y - 2. Substituting this into (g o f)(x) = x^2 + x + 6 yields g(y) = (y-2)^2 + (y-2) + 6 = y^2 - 3y + 8, which means g(x) = x^2 - 3x + 8.

Gaaffii 3

Which one of the following is incorrect about the relation R = {(x,y): y = (x+3)/(x+10)}?

  1. A.The range of R is (-∞,1) ∪ (1,∞)
  2. B.Domain of R is (-∞,-10) ∪ (-10,∞)
  3. C.R = {(x,y): y = (x+3)/(x+10)} can be a function
  4. D.The inverse of R is {(y,x): y = (10x+3)/(x+1)}
Deebii fi ibsa ilaalaa

Deebii: D The inverse of R is {(y,x): y = (10x+3)/(x+1)}

Maaliif

To find the inverse of y = (x+3)/(x+10), we solve for x to get x = (3-10y)/(y-1). Swapping the variables gives the inverse relation as y = (3-10x)/(x-1), which does not match option D.

Gaaffii 4

Which one of the following is correct one-to-one correspondence?

  1. A.f: ℝ → ℝ given by f(x)=log_a x, ∀x∈ℝ
  2. B.f: ℝ → ℚ given by f(x)=4^x, ∀x∈ℝ
  3. C.f: [0,∞) → [0,∞) given by f(x)=x^2, ∀x∈ℝ
  4. D.f: [1,∞) → (3,∞) given by f(x)=-3+√(x-1), ∀x∈ℝ
Deebii fi ibsa ilaalaa

Deebii: C f: [0,∞) → [0,∞) given by f(x)=x^2, ∀x∈ℝ

Maaliif

For the domain [0, ∞) and codomain [0, ∞), the function f(x) = x^2 is strictly increasing, making it one-to-one, and its range is [0, ∞), making it onto (hence a one-to-one correspondence).

Gaaffii 6

Which one of the following is not a rational expression?

  1. A.(x^5+9)/(x^2-16)
  2. B.√((x+2)^2)/(x^2-4)
  3. C.∛((x+2)^6)/(x^2-25)
  4. D.∛((x+2)^12)/(x^2+16)
Deebii fi ibsa ilaalaa

Deebii: B √((x+2)^2)/(x^2-4)

Maaliif

A rational expression is the quotient of two polynomials. In option B, the numerator simplifies to |x+2| because of the square root of a square, which is not a polynomial, making the entire expression non-rational.

Gaaffii 8

What is the solution set of the expression (36x-72)/(-x^3+4x) = [ (x-1)/(x+1) - (x+1)/(x-1) ] / [ (x+2)/(x^2-1) ] ?

  1. A.{-3,-2}
  2. B.{-3,3}
  3. C.{3,2}
  4. D.{3,3}
Deebii fi ibsa ilaalaa

Deebii: B {-3,3}

Maaliif

Simplifying both sides yields -36 / (x(x+2)) = -4x / (x+2). For x ≠ -2, this simplifies further to x^2 = 9, giving the solutions x = 3 and x = -3, both of which are valid since they do not violate any domain restrictions.

Qormaata guutuu PDF dhaan buufadhaa

Gaaffilee 36 kuusaa kana keessa jiran hunda akka waraqaa qormaataa maxxanfameetti, furtuu deebii ibsa 36 waliin immoo akka faayilii lammaffaatti. Maxxansaa yookiin daataa malee dubbisaa.

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Qormaatilee Herregaa biroo bara 2013 A.L.I

2013 A.L.I (2021)

Qormaatilee Herregaa kan waggoota biroo

2018 A.L.I (2026)2018 A.L.I (2026), damee hawaasaa2018 A.L.I (2026), maxxansa 12018 A.L.I (2026), maxxansa 22018 A.L.I (2026), maxxansa 32018 A.L.I (2026), maxxansa 42018 A.L.I (2026), maxxansa 52018 A.L.I (2026), maxxansa 62017 A.L.I (2025)2017 A.L.I (2025), damee uumamaa2017 A.L.I (2025), maxxansa 12017 A.L.I (2025), maxxansa 22017 A.L.I (2025), maxxansa 42016 A.L.I (2024)2016 A.L.I (2024), damee uumamaa2016 A.L.I (2024), damee hawaasaaFakkeenyaa, bara 2016 A.L.I2015 A.L.I (2023)2015 A.L.I (2023), damee uumamaa2015 A.L.I (2023), damee hawaasaa2014 A.L.I (2022)2014 A.L.I (2022), damee hawaasaa2011 A.L.I (2019)2009 A.L.I (2017)2008 A.L.I (2016)2007 A.L.I (2015)2006 A.L.I (2014)2005 A.L.I (2013)

Qormaatilee kana fakkaatan dabalataa

Qormaatilee Herregaa kutaa 12ffaa hundaQormaatilee bara 2013 A.L.I hundaGosa barnootaa fi bara hunda

Qormaata kana taa'uu dura Herregaa qayyabadhu

Yaadannoon gabaabaan Herregaa kutaa 12 kaardii 32 qaba. Tokkoon tokkoon boqonnaa boqonnaadhaan kitaaba biyyaalessaa irraa qophaa'ee seericha, mallattoowwan isaa maal bakka akka bu'an fi dogoggora qabxii nama dhabsiisu ni ibsa.

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Kunneen gaaffilee dhugaa qormaata galuumsa Herregaa bara 2013 A.L.I ti?

Eeyyee. Qormaata galuumsa yunivarsiitii biyyaalessaa kan Herregaa barattoonni bara 2013 A.L.I (2021) fudhatan irraa fudhataman. Kuusaan keenya gaaffilee isaa 36 qaba; tokkoon tokkoon isaanii deebii fi ibsa gara kitaaba barnootaatti qajeelchu qabu.

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Lakkoofsa bilbilaatiin herrega bilisaa banadhaa. Qormaatichi guutuun qormaata fakkeenyaa sa'aatiin daangeffame ta'ee qabxii battalumaa kenna; fooyya'iinsi gargaaraa AI ji'atti qarshii 199 kan ta'e waan isin jalaa darbe hunda isinii ibsa.

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Eeyyee; bilisas. Waraqaan gaaffii faayilii tokko, furtuun deebii ibsa isaa waliin immoo faayilii biraa ti; kanaaf qormaata dursitanii yaaluu dandeessu. Maxxansaa, yookiin yeroo daataan hin jirre irra deebiif bilbila keessan irratti kaa'adhaa.

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