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Qormaata galuumsa kutaa 12ffaa Herregaa, bara 2015 A.L.I (2023)

Gaaffilee dhugaa qormaata galuumsa yunivarsiitii kutaa 12 kan Herregaa, akkuma barattoonni bara 2015 A.L.I itti fudhatanitti. Tokkoon tokkoon gaaffii deebii sirrii fi ibsa qaba.

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  • 2015 A.L.I (2023)

    Bara qormaataa

  • Gaaffilee 57 deebii waliin

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Gaaffii 1

If f(x)=x+2x+2f(x) = \frac{\sqrt{x + 2}}{x + 2} and g(x)=1x−2g(x) = \frac{1}{x} - 2 then what is the value of f(g(x))f(g(x)) for all x>0x > 0 ?

  1. A.√x - 2
  2. B.√x + 2
  3. C.√x
  4. D.1/√x
Deebii fi ibsa ilaalaa

Deebii: C √x

Maaliif

Substituting g(x)=1x−2g(x) = \frac{1}{x} - 2 into f(x)f(x) gives f(g(x))=(1/x−2)+2(1/x−2)+2=1/x1/x=xx=xf(g(x)) = \frac{\sqrt{(1/x - 2) + 2}}{(1/x - 2) + 2} = \frac{\sqrt{1/x}}{1/x} = \frac{x}{\sqrt{x}} = \sqrt{x} for all x>0x > 0.

Gaaffii 2

Which of the following is Not the property of f(x)=x2/5f(x) = x^{2/5}?

  1. A.f(xy) = f(x)f(y)
  2. B.decreasing on (-∞,0]
  3. C.the range is real number
  4. D.the graph is symmetric with respect to the y-axis
Deebii fi ibsa ilaalaa

Deebii: C the range is real number

Maaliif

Since f(x)=x2/5=(x1/5)2f(x) = x^{2/5} = (x^{1/5})^2 is always non-negative for all real numbers xx, its range is [0,∞)[0, \infty), not the set of all real numbers.

Gaaffii 4

Which one of the following function is one to one correspondence function from A = [0,1] to B = [2,3]?

  1. A.f(x)=x+2
  2. B.f(x)=2x+2
  3. C.f(x)=x+3
  4. D.f(x)=2x+1
Deebii fi ibsa ilaalaa

Deebii: A f(x)=x+2

Maaliif

For a function to be a bijection from [0,1][0, 1] to [2,3][2, 3], it must map the endpoints to the endpoints. For f(x)=x+2f(x) = x + 2, we have f(0)=2f(0) = 2 and f(1)=3f(1) = 3, and since it is strictly increasing and linear, it is a one-to-one correspondence.

Gaaffii 6

Suppose f(x)=Q(x)x(x2−1)f(x) = \frac{Q(x)}{x(x^2 - 1)} where Q(x)Q(x) is a quadratic function. Which one of the following is necessarily true about the graph ff ?

  1. A.x=0, x=1 and x=-1 are vertical asymptote of the graph f
  2. B.The graph of f does not intersect with its horizontal asymptote.
  3. C.The vertical asymptote of the graph of f is only x=-1, if Q(x)=x^2-x
  4. D.The vertical asymptote of the graph of f is only x=1, if Q(x)=2x^2
Deebii fi ibsa ilaalaa

Deebii: C The vertical asymptote of the graph of f is only x=-1, if Q(x)=x^2-x

Maaliif

If Q(x)=x2−x=x(x−1)Q(x) = x^2 - x = x(x-1), the common factors xx and x−1x-1 in the numerator and denominator cancel out, leaving f(x)=1x+1f(x) = \frac{1}{x+1} (with holes at x=0x=0 and x=1x=1). Thus, the only vertical asymptote is x=−1x = -1.

Gaaffii 7

What is the solution set of 2x=x−2x2−2x=1−2x−23x−2\frac{2}{x} = \frac{x - 2}{x^2 - 2x} = 1 - \frac{2x - 2}{3x - 2} ? (Note: The equation has two equals signs, likely a typo; probably it is 2x=x−2x2−2x\frac{2}{x} = \frac{x - 2}{x^2 - 2x} and also equals the other expression. We solve as two equations.)

  1. A.{-2,1}
  2. B.{1,2}
  3. C.{-1}
  4. D.{1}
Deebii fi ibsa ilaalaa

Deebii: D {1}

Maaliif

By correcting the typo where the first minus sign was written as an equals sign, the equation 2x−x−2x2−2x=1−2x−23x−2\frac{2}{x} - \frac{x-2}{x^2-2x} = 1 - \frac{2x-2}{3x-2} simplifies to 1x=x3x−2\frac{1}{x} = \frac{x}{3x-2}, which yields x=1x = 1 and x=2x = 2. Since x=2x = 2 is excluded from the domain of the original expression, the only valid solution is x=1x = 1.

Gaaffii 8

Given line 4y=3x+244y = 3x + 24 and another line ℓ\ell parallel to this line at a distance of 4 units from it. A possible equation for ℓ\ell is

  1. A.y = (3/4)x
  2. B.y = (3/4)x + 1
  3. C.y = (3/4)x + 6
  4. D.y = (3/4)x - 6
Deebii fi ibsa ilaalaa

Deebii: B y = (3/4)x + 1

Maaliif

The distance between parallel lines 3x−4y+24=03x - 4y + 24 = 0 and 3x−4y+C=03x - 4y + C = 0 is given by ∣C−24∣32+(−4)2=4\frac{|C - 24|}{\sqrt{3^2 + (-4)^2}} = 4, which simplifies to ∣C−24∣=20|C - 24| = 20. This gives C=4C = 4, resulting in the line 3x−4y+4=03x - 4y + 4 = 0, or y=34x+1y = \frac{3}{4}x + 1.

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Gaaffilee 57 kuusaa kana keessa jiran hunda akka waraqaa qormaataa maxxanfameetti, furtuu deebii ibsa 57 waliin immoo akka faayilii lammaffaatti. Maxxansaa yookiin daataa malee dubbisaa.

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Kunneen gaaffilee dhugaa qormaata galuumsa Herregaa bara 2015 A.L.I ti?

Eeyyee. Qormaata galuumsa yunivarsiitii biyyaalessaa kan Herregaa barattoonni bara 2015 A.L.I (2023) fudhatan irraa fudhataman. Kuusaan keenya gaaffilee isaa 57 qaba; tokkoon tokkoon isaanii deebii fi ibsa gara kitaaba barnootaatti qajeelchu qabu.

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