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Qormaata galuumsa kutaa 12ffaa Herregaa, bara 2016 A.L.I (2024)

Gaaffilee dhugaa qormaata galuumsa yunivarsiitii kutaa 12 kan Herregaa, akkuma barattoonni bara 2016 A.L.I itti fudhatanitti. Tokkoon tokkoon gaaffii deebii sirrii fi ibsa qaba.

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  • 2016 A.L.I (2024)

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  • Gaaffilee 52 deebii waliin

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Gaaffii 1

Let pp and qq be propositions. Which one of the following propositions is equivalent to the proposition ¬p∨(p∧q)\neg p \lor (p \land q)?

  1. A.¬p∨¬q\neg p \lor \neg q
  2. B.p⇒qp \Rightarrow q
  3. C.¬p∧q\neg p \land q
  4. D.¬p⇒q\neg p \Rightarrow q
Deebii fi ibsa ilaalaa

Deebii: B p⇒qp \Rightarrow q

Maaliif

Using the distributive law, we have ¬p∨(p∧q)≡(¬p∨p)∧(¬p∨q)≡True∧(¬p∨q)≡¬p∨q\neg p \lor (p \land q) \equiv (\neg p \lor p) \land (\neg p \lor q) \equiv \text{True} \land (\neg p \lor q) \equiv \neg p \lor q, which is equivalent to the conditional statement p⇒qp \Rightarrow q.

Gaaffii 2

Which one of the following is NOT true about the function f(x)=tan⁡−1xf(x) = \tan^{-1} x?

  1. A.The line x=−π2x = -\frac{\pi}{2} is a vertical asymptote to the graph of ff.
  2. B.The graph of ff is the image of the graph of y=tan⁡xy = \tan x after it is reflected with respect to the line y=xy = x.
  3. C.The graph of ff intersects the xx-axis at (0,0)(0, 0).
  4. D.The line y=π2y = \frac{\pi}{2} is a horizontal asymptote to the graph of ff.
Deebii fi ibsa ilaalaa

Deebii: A The line x=−π2x = -\frac{\pi}{2} is a vertical asymptote to the graph of ff.

Maaliif

The domain of f(x)=tan⁡−1xf(x) = \tan^{-1} x is the entire set of real numbers R\mathbb{R}, and it has horizontal asymptotes at y=±π2y = \pm \frac{\pi}{2} but no vertical asymptotes. The line x=−π2x = -\frac{\pi}{2} is actually a vertical asymptote for y=tan⁡xy = \tan x, not for its inverse.

Gaaffii 3

Which one of the following statements is true?

  1. A.If xx and yy are integers and xx divides yy, then yy divides xx.
  2. B.If xx is an even integer and yy is an odd integer, then x2+y2x^2 + y^2 is odd.
  3. C.If xx and yy are even integers, then x+yx + y is an odd integer.
  4. D.If xx and yy are positive integers, then xy\frac{x}{y} is a positive integer.
Deebii fi ibsa ilaalaa

Deebii: B If xx is an even integer and yy is an odd integer, then x2+y2x^2 + y^2 is odd.

Maaliif

If xx is even, then x2x^2 is even; if yy is odd, then y2y^2 is odd. The sum of an even number and an odd number, x2+y2x^2 + y^2, is always odd.

Gaaffii 4

Let pp, qq, and rr be propositions. If pp is True , qq is False , and rr is False , which one of the following propositions has truth value True ?

  1. A.(p∧¬q)⇔(p∨r)(p \land \neg q) \Leftrightarrow (p \lor r)
  2. B.(q∧r)⇔(p∧¬r)(q \land r) \Leftrightarrow (p \land \neg r)
  3. C.p⇒(q∨r)p \Rightarrow (q \lor r)
  4. D.(p∨q)⇒r(p \lor q) \Rightarrow r
Deebii fi ibsa ilaalaa

Deebii: A (p∧¬q)⇔(p∨r)(p \land \neg q) \Leftrightarrow (p \lor r)

Maaliif

Substituting the truth values, we have p∧¬q≡True∧True≡Truep \land \neg q \equiv \text{True} \land \text{True} \equiv \text{True}, and p∨r≡True∨False≡Truep \lor r \equiv \text{True} \lor \text{False} \equiv \text{True}. Thus, (p∧¬q)⇔(p∨r)≡True⇔True(p \land \neg q) \Leftrightarrow (p \lor r) \equiv \text{True} \Leftrightarrow \text{True}, which is True.

Gaaffii 5

Which one of the following is the equation of the tangent line to the graph of f(x)=2x3−4x2+5x+3f(x) = 2x^3 - 4x^2 + 5x + 3 at the point (0,3)(0, 3)?

  1. A.3x+5y−3=03x + 5y - 3 = 0
  2. B.3x−5y−3=03x - 5y - 3 = 0
  3. C.5x−y+3=05x - y + 3 = 0
  4. D.5x+y+3=05x + y + 3 = 0
Deebii fi ibsa ilaalaa

Deebii: C 5x−y+3=05x - y + 3 = 0

Maaliif

The derivative of f(x)f(x) is f′(x)=6x2−8x+5f'(x) = 6x^2 - 8x + 5, which gives a tangent slope of f′(0)=5f'(0) = 5 at x=0x = 0. The equation of the tangent line is y−3=5(x−0)y - 3 = 5(x - 0), which simplifies to 5x−y+3=05x - y + 3 = 0.

Gaaffii 6

Let v=AB⃗v = \vec{AB} and w=CD⃗w = \vec{CD} be vectors in the plane, where A(1,−1)A(1, -1), B(2,−2)B(2, -2), C(−1,3)C(-1, 3), and D(4,−3)D(4, -3). Which one of the following is equal to v−wv - w?

  1. A.5i−6j5i - 6j
  2. B.i−15ji - 15j
  3. C.−4i+5j-4i + 5j
  4. D.4i−5j4i - 5j
Deebii fi ibsa ilaalaa

Deebii: C −4i+5j-4i + 5j

Maaliif

The vector v=B−A=(1,−1)=i−jv = B - A = (1, -1) = i - j and w=D−C=(5,−6)=5i−6jw = D - C = (5, -6) = 5i - 6j. Subtracting these gives v−w=(i−j)−(5i−6j)=−4i+5jv - w = (i - j) - (5i - 6j) = -4i + 5j.

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Kunneen gaaffilee dhugaa qormaata galuumsa Herregaa bara 2016 A.L.I ti?

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