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Unit notes and practice questions

Grade 11 Biology unit 3

Everything here is for unit 3 of the Grade 11 Biology textbook: what the chapter covers, the short notes, practice questions with their answers, and the lesson video where one exists.

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3
Cards
10
Practice questions on unit 3
79–112
The textbook pages for unit 3

What unit 3 covers

  1. 1.What are enzymes?
  2. 2.Properties and functions of enzymes
  3. 3.1General properties of an enzyme
  4. 4.2The function of enzymes
  5. 5.Protein structures
  6. 6.Enzyme substrate models
  7. 7.1Enzyme-substrate binding models
  8. 8.2Enzymatic transition state
  9. 9.Enzyme regulation
  10. 10.Types of enzymes
  11. 11.1Enzyme structural classification
  12. 12.2Basic classification of enzymes
  13. 13.Factors affecting enzyme action
  14. 14.1Description on factors affecting enzymatic actions
  15. 15.Enzyme kinetics
  16. 16.Application of enzymes in industries and their benefits
  17. 17.1Uses of enzyme application
  18. 18.Malting in Ethiopian tradition
  19. 19.Steps of modern malting
  20. 20.Why is malting for?

Short notes for unit 3

The cards filed under this chapter on the Grade 11 Biology page. Open one at a time.

V1=Vmax⁡[S]KM+[S]V_1 = \frac{V_{\max}[S]}{K_M + [S]}
V1V_1
Initial velocity of the enzymatic reactionmol L−1 s−1\text{mol}\,\text{L}^{-1}\,\text{s}^{-1}
Vmax⁡V_{\max}
Maximal velocity of the enzymatic reactionmol L−1 s−1\text{mol}\,\text{L}^{-1}\,\text{s}^{-1}
[S][S]
Substrate concentrationmol L−1\text{mol}\,\text{L}^{-1}
KMK_M
Michaelis constant, substrate concentration at half-maximal velocitymol L−1\text{mol}\,\text{L}^{-1}

When you use it

Use when relating the rate of an enzyme-catalyzed reaction to substrate concentration.

Watch out

KM represents the substrate concentration at half Vmax, not half the substrate concentration.

Drafted from Grade 11 Biology, pages 79-112, then checked twice before it went up

LevelDescription
PrimaryLinear sequence of amino acids linked together by peptide bonds.
SecondaryFolding into alpha-helix or beta-pleated sheets via hydrogen bonds.
TertiaryOverall three-dimensional shape formed by side-chain interactions.
QuaternarySpatial arrangement of multiple folded polypeptide subunits.

When you use it

Use when distinguishing between the four structural levels of enzyme proteins.

Watch out

Primary structure is held exclusively by covalent peptide bonds, while secondary and higher structures rely on hydrogen and side-chain bonds.

Drafted from Grade 11 Biology, pages 79-112, then checked twice before it went up

ClassCatalytic Function
OxidoreductasesCatalyze oxidation-reduction reactions and electron transfer.
TransferasesTransfer functional groups from a donor to an acceptor.
HydrolasesCatalyze the cleavage of chemical bonds by hydrolysis.
LyasesCleave bonds by means other than hydrolysis or oxidation.
IsomerasesConvert molecules from one structural isomer to another.
LigasesJoin two molecules coupled with di-phosphate bond cleavage in ATP.

When you use it

Use when classifying enzymes by the chemical reaction type they catalyze.

Watch out

Lyases break chemical bonds without water or oxidation, whereas hydrolases require water.

Drafted from Grade 11 Biology, pages 79-112, then checked twice before it went up

Practice questions on unit 3

10 multiple-choice questions written against this chapter, each with its answer and the reason. Try one before you open the answer.

Question 1

Which enzyme found in human saliva helps to break down starches into sugars?

  1. A.Lipase
  2. B.Amylase
  3. C.Helicase
  4. D.Trypsin
Show the answer and why

Answer: B Amylase

Why

According to the textbook, amylase is present in saliva and converts starches into simpler sugars.

Question 2

What is the inactive protein part of a conjugated enzyme called before it joins with a cofactor?

  1. A.Apoenzyme
  2. B.Holoenzyme
  3. C.Coenzyme
  4. D.Prosthetic group
Show the answer and why

Answer: A Apoenzyme

Why

A conjugated enzyme (holoenzyme) is made of a protein part called the apoenzyme, which is inactive on its own, and a non-protein part called a cofactor.

Question 3

What is the first step in the traditional Ethiopian malting process used to prepare grains for beverages like tella?

  1. A.Kilning
  2. B.Steeping
  3. C.Boiling
  4. D.Distilling
Show the answer and why

Answer: B Steeping

Why

The three main steps of malting are steeping (soaking the grains in water), germinating (sprouting), and kilning (heating/drying).

Question 4

Which class of enzymes catalyzes the transfer of functional groups, such as a methyl group, from one molecule to another?

  1. A.Lyases
  2. B.Isomerases
  3. C.Transferases
  4. D.Hydrolases
Show the answer and why

Answer: C Transferases

Why

Transferases are enzymes that transfer functional groups (like methyl groups) from a donor molecule to an acceptor molecule.

Question 5

Why do enzymes exhibit a colloidal nature that allows little or no dialysis across a semipermeable membrane?

  1. A.Because they have a high molecular weight and large size
  2. B.Because they are insoluble in water
  3. C.Because they carry no electrical charge
  4. D.Because they are easily destroyed by cold temperatures
Show the answer and why

Answer: A Because they have a high molecular weight and large size

Why

The textbook states that the colloidal property of enzymes is their tendency to show little or no movement across semipermeable membranes because of their large size or high molecular weight.

Question 6

In the secondary structure of proteins, how is the right-handed coiled strand of an α-helix held stable?

  1. A.By peptide bonds formed only between side chains
  2. B.By hydrogen bonds between N-H and C=O groups
  3. C.By covalent bonds between metal cofactors
  4. D.By lipid attachments on the outside
Show the answer and why

Answer: B By hydrogen bonds between N-H and C=O groups

Why

The α-helix is stabilized by hydrogen bonding between the hydrogen of the N-H group and the oxygen of the C=O group of amino acid residues.

Question 7

Which type of inhibitor binds only to the enzyme-substrate complex and not to the free enzyme?

  1. A.Competitive inhibitor
  2. B.Uncompetitive inhibitor
  3. C.Irreversible inhibitor
  4. D.Allosteric activator
Show the answer and why

Answer: B Uncompetitive inhibitor

Why

An uncompetitive inhibitor binds only to the enzyme-substrate complex (ES) rather than the free enzyme, slowing down the reaction.

Question 8

In the food industry, which enzyme is commonly used to tenderize meat for cooking?

  1. A.Papain
  2. B.Rennin
  3. C.Ligninase
  4. D.Mannanase
Show the answer and why

Answer: A Papain

Why

Papain has culinary uses specifically for tenderizing meat before cooking.

Question 9

During modern and traditional malting, why must the green malt undergo kilning (heating)?

  1. A.To stop germination so the growing plant does not consume all the starch reserves
  2. B.To completely denature all amylase and protease enzymes
  3. C.To increase moisture so bacteria can ferment the grain directly
  4. D.To convert the barley husks into pure glucose
Show the answer and why

Answer: A To stop germination so the growing plant does not consume all the starch reserves

Why

Kilning dries the green malt and halts further growth. If germination continued, the growing seedling would use up all the starch reserves needed for brewing.

Question 10

How does a prosthetic group differ from a coenzyme in the structural classification of enzymes?

  1. A.A prosthetic group is firmly attached (often a metal ion), while a coenzyme is loosely attached (often a vitamin B complex).
  2. B.A prosthetic group is a protein, while a coenzyme is a lipid molecule.
  3. C.A prosthetic group is loosely bound, while a coenzyme is permanently welded by peptide bonds.
  4. D.A prosthetic group acts as an inhibitor, while a coenzyme is always an activator.
Show the answer and why

Answer: A A prosthetic group is firmly attached (often a metal ion), while a coenzyme is loosely attached (often a vitamin B complex).

Why

The non-protein cofactor part is classified into firmly attached prosthetic groups (usually metal ions) and loosely attached coenzymes (usually vitamin B complex molecules).

The app holds 12 questions on this unit, marked as you go. These are the first 10.

The textbook pages for unit 3

Unit 3 runs from page 79 to page 112 of the Ministry of Education edition.

Ministry of Education edition, English, 294 pages

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